Answer:
C. ∠SRT≅∠VTR and ∠STR≅∠VRT
Step-by-step explanation:
Given:
Quadrilateral is a parallelogram.
RS║VT; RT is an transversal line;
Hence By alternate interior angle property;
∠SRT≅∠VTR
∠STR≅∠VRT
Now in Δ VRT and Δ STR
∠SRT≅∠VTR (from above)
segment RT= Segment RT (common Segment for both triangles)
∠STR≅∠VRT (from above)
Now by ASA theorem;
Δ VRT ≅ Δ STR
Hence the answer is C. ∠SRT≅∠VTR and ∠STR≅∠VRT
Answer:
x=5
Step-by-step explanation:
If ABCD is a parallelogram, then AB = CD
AB=CD
6x-10 = 3x+5
Subtract 3x from each side
6x-3x -10 = 3x-3x+5
3x-10 = 5
Add 10 to each side
3x-10+10 = 5+10
3x = 15
Divide by 3 on each side
3x/3 =15/3
x=5
Answer:
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Step-by-step explanation:
