5 consecutive even integers: 2n, 2n+2, 2n+4, 2n+6, 2n+8 for any integer n The sum of the two smallest of five consecutive even integers is 50 less than the sum of the other three integers: 2n + 2n+2 = 2n+4 + 2n+6 + 2n+8 - 504n + 2 = 6n -3234 = 2nn = 17 <span>The smallest integer in our sequence is 2n = 2*17 = 34</span> Check:2n + 2n+2 = 2n+4 + 2n+6 + 2n+8 - 5034 + 36 = 38 + 40 + 42 - 5070 = 120 - 5070 = 70
Expand the right side:
Notice that 98 = 2 * 7 * 7, so we have 
and 
.
Then
and
Answer:
c
the total number of marbles are 12 and there are 3 colours so you divide 12 by 3
Answer:
F^-1 (x) = 3x/2+5/4
Step-by-step explanation:
First, replace f(x) with y
Replace every x with a y and replace every y with an x .
Solve the equation from Step 2 for y
Replace y with f−1(x) f − 1 ( x )
Verify your work by checking that (f∘f−1)(x)=x ( f ∘ f − 1 ) ( x ) = x and (f−1∘f)(x)=x ( f − 1 ∘ f ) ( x ) = x are both true.
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Answer:
31 and -31
Step-by-step explanation:
