The runner ran 5/6 then he ran 9/10 more how much did he run in all
Answer:
1.
%K = 31.904%
%Cl = 28.930%
%O = 39.166%
2.
Hg = 80.69/ 200.59 = 0.40/0.2 = 2
S = 6.436/ 32.07 = 0.20/0.2 = 1
O = 12.87/ 16.00 = 0.80/0.2 = 4
Hg2SO4 is the empirical formula
Step-by-step explanation:
If "d" is used to represent the depth of the river, that product will be
86d
