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Colt1911 [192]
3 years ago
8

Plz help me it's due today​

Mathematics
1 answer:
lilavasa [31]3 years ago
3 0

Answer:

I can't see the half of the question before city

Step-by-step explanation:

Then i woul dbe able to help u

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In the construction of the circumcenter, why do you only need to construct two perpendicular bisectors, and not all three?
Wittaler [7]
We know that the Circumcenter is the intersection of a triangle's right (perpendicular) bisectors. Once you have found two of these you can determine their point of intersection. 

It is a proven mathematical concept that the third perpendicular bisector will also cross through this intersection point. While it is not necessary to construct all three it is often done so to verify that the intersection of the first two perpendicular bisectors was in fact correct.
7 0
3 years ago
What is the result of 54,000 X 1,200 written in scientific notations
Anna [14]

Answer:

54000 \times 1200 = 64800000 = 6.48 \times 10^{7}

4 0
3 years ago
What is the value of s?
beks73 [17]

Answer:

To what

Step-by-step explanation:

3 0
3 years ago
HELP!! I NEED THIS QUICKLY
Elza [17]

Answer:

A and D

Step-by-step explanation:

We are given that

(3/4,2/3),(1/4,1),(1,1/2) and (1/2,1)

x_1=\frac{3}{4}

y_1=\frac{2}{3}

x_2=\frac{1}{4},y_2=1

x_3=1,y_3=\frac{1}{2}

x_4=\frac{1}{2},y_4=1

k=\frac{1}{2}

Direct proportion:

\frac{x}{y}=k

Inverse proportion:xy=k

\frac{x_1}{y_1}=\frac{3}{4}\times \frac{3}{2}=\frac{9}{8}\neq \frac{1}{2}

Therefore, it is not in direct proportion.

\frac{1}{4\times 2}=\frac{1}{8}\neq\frac{1}{2}

\frac{1}{\frac{1}{2}}=2\neq \frac{1}{2}

x_1y_1=\frac{3}{4}\times \frac{2}{3}=\frac{1}{2}

x_2y_2=\frac{1}{4}\times 2=\frac{1}{2}

x_3y_3=1\times \frac{1}{2}=\frac{1}{2}

x_4y_4=\frac{1}{2}\times 1=\frac{1}{2}

Therefore, xy=k=\frac{1}{2}

Hence, the given points form an inverse variation .

xy=\frac{1}{2}

y=\frac{1}{2x}

Option A and D is true.

6 0
3 years ago
The sum of two numbers is 27. The larger number is 3 more than the smaller number. What are the two numbers?
pantera1 [17]

The two numbers are 12 and 15

<em><u>Solution:</u></em>

Let the smaller number be "x"

Let the larger number be "y"

Given that,

<em><u>The sum of two numbers is 27</u></em>

Therefore, we frame a equation as:

Smaller number + Larger number = 27

x + y = 27 ------ eqn 1

<em><u>The larger number is 3 more than the smaller number</u></em>

Larger number = 3 + smaller number

y = 3 + x ------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

<em><u>Substitute eqn 2 in eqn 1</u></em>

x + 3 + x = 27

2x + 3 = 27

2x = 27 - 3

2x = 24

<h3>x = 12</h3>

<em><u>Substitute x = 12 in eqn 2</u></em>

y = 3 + 12

<h3>y = 15</h3>

Thus the two numbers are 12 and 15

7 0
3 years ago
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