Question

What is the y-intercept of the equation of the line that is perpendicular to the line y =

Answer 1

Answer:

$y$ intercept $=10$

line $y=-x+10$

Step-by-step explanation:

Let $y=mx+b$ is the required line.

Slope of perpendicular lines : If $m_{1}$ and $m_{2}$ be slope of two perpendicular lines. Them $m_{1}\times m_{2}=-1$

$y=mx+b$ is perpendicular to $y=x+10$

the slope of $y=x+10$  is $=1$

$m\times 1=-1\\m=-1$

Hence eqn is $y=-x+b$

This equation passes through $(15,-5)$

$-5=-15+b\\b=-5+15\\b=10$

so the line is $y=-x+10$

y-intercept :

Substitute $x=10$

$y=0+10\\y=10$