If VX = WZ = 40 cm and m∠ZVX = m∠XWZ = 22°, can ΔVZX and ΔWXZ be proven congruent by SAS? Why or why not?

Mathematics

2 answers:

Taya2010 [7]3 years ago

5 0

The answer is D. No, there is not enough given information.

devlian [24]3 years ago

3 0

The answer is D i just took the quiz.

You might be interested in

Solve for x<br> x - 8 = sqrt2x+8

Svetlanka [38]

Answer:

x=4

Step-by-step explanation:

to get rid of the square root on the right you square both sides so

2x+8=x^2

Then bring

2x+8

to the left so you have 0=(x^2)−2x+8

Now you can do the quadratic formula to find the zeroes

6 0

3 years ago

Read 2 more answers

What is the common ratio of the geometric sequence below?

Vadim26 [7]

Answer:

$\textbf{Option C - $0.1$}\\$

Step-by-step explanation:

$\textup{A geometric series is given by}\\$ a, ar, ar^2, ar^3,. . . , ar^{n-1}, ar^n $ \\\textup{\textbf{Geometric progression or GP is a sequence of numbers in which the next number in the sequence is obtained by multiplying a number to the previous number in the sequence.}}\\$

$\textup{This number is constant through out the sequence and is denoted by $r$. it is given by $r = \frac{ar^n}{ar^{n-1}}$} \\$

$\textup{Here, the given sequence is: $70, 7, 0.7,...$}\\$

$$i.e., a = 70, ar = 7$\\$

$\textup{Hence, $r = \frac{ar}{a} = \frac{7}{70}$ }\\$

$= \frac{1}{10} = 0.1$

7 0

3 years ago

Which expression simplifies...

Zina [86]

Answer:

see below

Step-by-step explanation:

If suffices to look at the last term. It must simplify to 4/(3w²), so the exponents of z must match in numerator and denominator, and the ratio of constants must reduce to 4/3.

The exponents of z have the right values in choices B and D, but the ratio of constants only matches in choice D. Looking at the rest of choice D, we see that we can factor 6w²z² from both numerator and denominator, then factor 2 from the remaining numerator to make it match the desired form.

$\dfrac{(12w^2z^4-24w^2z^2)}{18w^4z^2}=\dfrac{6w^2z^2}{6w^2z^2}\cdot\dfrac{2z^2-4}{3w^2}=\dfrac{2(z^2-2)}{3w^2}$