Question

Solve the system of equations algebraically.

Answer 1

Answer: d. (17, 20)

Step-by-step explanation:

We have the following system of equations:

$x-3y=8$ (1)

$5x-4y=5$ (2)

Isolating $x$ from (1):

$x=\frac{8+3y}{4}$ (3)

Substituting (3) in (2):

$5(\frac{8+3y}{4})-4y=5$ (4)

Isolating $y$:

$\frac{40}{4}+\frac{15 y}{4}-4y=5$ (5)

$10-5=4y-\frac{15 y}{4}$ (6)

$y=20$ (7)

Substituting (7) in (1):

$x-3(20)=8$ (8)

Isolating $x$:

$x=17$ (9)

Hence, the correct option is d. (17, 20)