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Hitman42 [59]
3 years ago
13

Honestly if anyone could help be understand how to solve these by factoring, that would be great! Thank you!

Mathematics
1 answer:
fiasKO [112]3 years ago
8 0

Answer:

1) Option 3

2) Option 3

3) Option 3

4) Option 1

5) Option 2

6) Option 3

7) Option 1

Step-by-step explanation:

1) y = x^2 + 4x + 3

Lets split the middle term.

=> y = x^2 + 3x + x + 3

=> y = x(x+3) + 1(x + 3)

=> y = (x+1)(x+3)

∴ x = -3 , -1

2) y = 8x^2 - 22x + 5

Lets split the middle term.

=> y = 8x^2 - 20x - 2x + 5

=> y = 4x(2x - 5) - 1(2x - 5)

=> y = (2x - 5)(4x - 1)

∴ x =\frac{1}{4}  , \frac{5}{2}

3) y = x^2 - 5x

=> y = x(x - 5)

∴ x = 0 , 5

4) y = 12x^2 + 18x

=> y = 6x(2x + 3)

∴ x = \frac{-3}{2} , 0

5) y = x^2 - 7x + 12

Lets split the middle term.

=> y = x^2 -3x - 4x + 12

=> y = x(x - 3) - 4(x - 3)

=> y = (x - 3)(x - 4)

∴ x = 3,4

6) y = 3x^2 + 10x + 8

Lets split the middle term.

=> y = 3x^2 + 6x + 4x + 8

=> y = 3x(x + 2) + 4(x + 2)

=> y = (x + 2)(3x + 4)

∴ x = -2 , \frac{-4}{3}

7) y = x^2 - 4x - 45

Lets split the middle term.

=> y = x^2 - 9x + 5x - 45

=> y = x(x - 9) + 5(x - 9)

=> y = (x - 9)(x + 5)

∴ x = -5 , 9

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