2(4z−2) = 44
Simplify both sides of the equation.
Distribute:
(2)(4z)+(2)(−2) = 44
8z + −4 = 44
8z − 4 = 44
Add 4 to both sides.
8z − 4 + 4 = 44 + 4
8z = 48
Divide both sides by 8
8z/8 48/8
z = 6
5*4/4 +1/4
20/4+1/4
21/4
You can multiply the whole number by 1, for the same number...but in the terms you need...for example, 5/5=1, but by multiplying by that, you'll get the number /5
Answer:
-4x^2, -3x, -5
Step-by-step explanation:
-4x^2 + 2x - 5 (1 + x)
-4x^2 + 2x - 5 + 5x
-4x^2 - 3x - 5
Answer:
Inverse sine
Step-by-step explanation:
Recall the three common trig ratios
Remember SohCahToa
Sine = Opposite over Hypotenuse (SOH)
Cosine = Adjacent over Hypotenuse (CAH)
Tangent = Opposite over Adjacent (TOA)
Now let's look back at the question
It asks us which inverse function would we use to solve for angle Z
Looking at angle Z, we are given it's opposite side length and the hypotenuse ( longest side ).
When dealing with the opposite side length and hypotenuse we use trig function sine.
When trying to find the angle we use inverse so we would use inverse sine to find the measure of angle A
Question:
Jim has 19,700 g of sand in his sandbox. He brings home another 6,300 g of sand from the beach to add to his. How many kilograms of sand does Jim have in his sandbox now?
Answer:
The amount of kilogram of sand Jim now has in his sand box is 26.00 kg
Step-by-step explanation:
The question relates to the method of addition or adding numbers.
Here, we note that the initial mass of sand in the sandbox = 19700 g
Added mass of sand to the sandbox = 6,300 g
Therefor the total mass of sand in the sand box is given by;
19,700 + 6,300 = 26,000 g
Therefore, the amount of kilogram of sand Jim now has in his sand box is 26,000 g which is equal to 26000/1000 = 26.00 kg.