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Sergeeva-Olga [200]
3 years ago
5

Using the relation dS = (δQ/T)int rev for the definition of entropy, calculate the change in the specific entropy of R-134a as i

t is heated at a constant pressure of 120 kPa from a saturated liquid to a saturated vapor. Use the tables for R-134a.
Chemistry
1 answer:
pashok25 [27]3 years ago
7 0

Answer:

The value of specific entropy = 0.847 \frac{KJ}{kg K}

Explanation:

Constant pressure = 120 K pa

From the property tables of R - 134 a at P = 120 K pa

Temperature T = - 22.5 ° c

Value of heat transfer = 212.32 \frac{KJ}{kg}

Thus entropy change ΔS = \frac{dq}{T}

⇒ ΔS = \frac{212.32}{250.5}

⇒ ΔS = 0.847 \frac{KJ}{kg K}

Therefore the value of specific entropy = 0.847 \frac{KJ}{kg K}

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