Answer:
1. 3
2. 23
3. 50
4. 26%
5. 24%
Step-by-step explanation:
34% of the scores lie between 433 and 523.
Solution:
Given data:
Mean (μ) = 433
Standard deviation (σ) = 90
<u>Empirical rule to determine the percent:</u>
(1) About 68% of all the values lie within 1 standard deviation of the mean.
(2) About 95% of all the values lie within 2 standard deviations of the mean.
(3) About 99.7% of all the values lie within 3 standard deviations of the mean.
![$Z(X)=\frac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=%24Z%28X%29%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
![$Z(433)=\frac{433-\ 433}{90}=0](https://tex.z-dn.net/?f=%24Z%28433%29%3D%5Cfrac%7B433-%5C%20433%7D%7B90%7D%3D0)
![$Z(523)=\frac{523-\ 433}{90}=1](https://tex.z-dn.net/?f=%24Z%28523%29%3D%5Cfrac%7B523-%5C%20433%7D%7B90%7D%3D1)
Z lies between o and 1.
P(433 < x < 523) = P(0 < Z < 1)
μ = 433 and μ + σ = 433 + 90 = 523
Using empirical rule, about 68% of all the values lie within 1 standard deviation of the mean.
i. e. ![((\mu-\sigma) \ \text{to} \ (\mu+\sigma))=68\%](https://tex.z-dn.net/?f=%28%28%5Cmu-%5Csigma%29%20%5C%20%5Ctext%7Bto%7D%20%5C%20%28%5Cmu%2B%5Csigma%29%29%3D68%5C%25)
Here μ to μ + σ = ![\frac{68\%}{2} =34\%](https://tex.z-dn.net/?f=%5Cfrac%7B68%5C%25%7D%7B2%7D%20%3D34%5C%25)
Hence 34% of the scores lie between 433 and 523.
Hello!!!
Answer:
11 cups of chocolate chips
Step-by-step explanation:
If we use the information we got from the problem we can see that 8 gives us 12. So all we need to do is add more to the orignal number(8) unitll we get 15. So 11 cups gives us 15 cookies.
Have a nice day!!!
No it does not. Any function that has any of the same X vaules (The line going up left to right) is not a function.
Answer:
is that all
Step-by-step explanation:
if she runs 24 laps a minute then the next minute she would of ran 48