This question is a little complicated so I will try my best to answer this question.
First do process of elimination which means think of the wrong answers and at
last you will get a correct answer which is 784 according to formula it is the
correct answer.
What are the expressions?
For a probability distribution the expected value is the summation of product of probabilities with their respective data values. Let x be the probability that Jackson goes gym for 2 days and y be the probability that he goes gym for 3 days.
For the given case we have following values and their probabilities:
0 : 0.1
2 : x
3 : y
So the expected value will be = 0(0.1) + 2(x) + 3(y)
Expected value is given to be 2.05. So we can write the equation as:
2x + 3y = 2.05 (Equation 1)
Also for a probability distribution, the sum of probabilities must always equal to 1. So we can set up the second equation as:
0.1 + x + y = 1
x + y = 0.9 (Equation 2)
From Equation 2 we can write the value of x to be x = 0.9 - y. Using this value in equation 1, we get:
2(0.9 - y) + 3y = 2.05
1.8 - 2y + 3y = 2.05
1.8 + y = 2.05
y = 0.25
Using the value of y in equation 2 we get value of x to be 0.65
Therefore we can conclude that:
The probability that Jackson goes to gym for 2 days is 0.65 and the probability that he goes to gym for 3 days is 0.25
Answer:
3
Step-by-step explanation:
In this case, Luis has 6 quarters, and 3 dimes. 6 - 3 = 3, and it works out to the following:
6 • 0.25 = 1.50
3 • 0.10 = 0.30
1.50 + 0.30 = 1.80
Answer:
Step-by-step explanation:
