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raketka [301]
3 years ago
14

Compare the following functions to determine which has a greater rate of change.

Mathematics
2 answers:
emmainna [20.7K]3 years ago
6 0
D is the answer, explanation is because if you look in a bookmark you can see
atroni [7]3 years ago
4 0

\text{Hello there!}\\\\\text{Lets see if the rate of change for the two functions are the same}\\\\\text{We know that the rate of change for the first function is -2/3}\\\text{Lets find the rate of change for the second function}\\\\\text{We will use}\,\,\frac{y2-y1}{x2-x1}\,\,\text{to find the rate of change}\\\\\text{Plug in the coordinates:}\\\\\frac{3-5}{3-0}\\\\\text{Solve:}\\\\\frac{3-5}{3-0}\\\\\frac{-2}{3} = \text{rate of change for function 2}\\

\text{The rate of change is the same for both functions}\\\\\text{This means that:}\\\\\large\boxed{\text{Answer: C. Function 1 and Function 2 have the same rate of change.}}

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Trava [24]
Overestimate because the answer is 1.61
7 0
3 years ago
Read 2 more answers
A stamp has the Length of 1/2 cm and a width of 1 1/2 is the area of the stamps
avanturin [10]

Answer:

Area =  \frac{3}{4} cm^2

Step-by-step explanation:

Given

Length =\frac{1}{2}\ cm

Width = 1\frac{1}{2}\ cm

Required

Determine the Area

Area is calculated as follows

Area = Length * Width

Substitute values for Length and Width

Area = \frac{1}{2} * 1\frac{1}{2}

Convert mixed fraction

Area = \frac{1}{2} * \frac{3}{2}

Area =  \frac{3}{4}

Hence, the area is

Area =  \frac{3}{4} cm^2

3 0
2 years ago
A travel agent currently has 80 people signed up for a tour. The price of a ticket is $5000 per person. The agency has chartered
Nikolay [14]
So hmm let's take a peek at the cost first

so, they chartered the plane for 150 folks with a fixed cost of 250,000
now, incidental fees are 300 per person, if we use the quantity "x", for how many folks, then if "x" persons are booked, then incidental fees are 300x

so, more than likely an insurance agency is charging them 300x for coverage

anyway, thus the cost C(x) = 250,000 + 300x

now, the Revenue R(x), is simple is jut price * quantity

well, the price, thus far we know is 5000 for 80 folks, but it can be lowered by 30 to get one more person, thus increasing profits

so... let's see what the price say y(x) is  \bf \begin{array}{ccllll}
quantity(x)&price(y)\\
-----&-----\\
80&5000\\
81&4970\\
82&4940\\
83&4910
\end{array}\\\\
-----------------------------\\\\

\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%   (a,b)
&({{ 80}}\quad ,&{{ 5000}})\quad 
%   (c,d)
&({{ 83}}\quad ,&{{ 4910}})
\end{array}
\\\quad \\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{-90}{3}\implies -30
\\ \quad \\\\
% point-slope intercept
y-{{ 5000}}={{ -30}}(x-{{ 80}})\implies y=-30x+2400+5000\\
\left.\qquad   \right. \uparrow\\
\textit{point-slope form}
\\\\\\
y=-30x+7400

so.. now we know y(x) = -30x+7400

now, Revenue is just price * quantity
the price y(x) is -30x+7400, the quantity is "x"

that simply means R(x) = -30x²+7400x


now, for the profit P(x)

the profit is simple, that is just incoming revenue minus costs, whatever is left, is profit
so P(x) = R(x) - C(x)

P(x) = (7400x - 30x²) - (250,000+300x)

P(x) = -30x² + 7100x - 250,000

now, where does it get maximized? namely, where's the maximum for P(x)?

well \bf \cfrac{dp}{dx}=-60x+7100

and as you can see, if you zero out the derivative, there's only 1 critical point, run a first-derivative test on it, to see if its a maximum
7 0
3 years ago
Write the number described by 1 ten 16 ones
Hatshy [7]
Kind of confusing....if it was 1 ten and 6 ones it'd be 16....  So with that, the answer to this would be 26
3 0
3 years ago
What’s 3.8 - (-7.45)
Varvara68 [4.7K]

it is 11.25................................

6 0
3 years ago
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