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raketka [301]
3 years ago
14

Compare the following functions to determine which has a greater rate of change.

Mathematics
2 answers:
emmainna [20.7K]3 years ago
6 0
D is the answer, explanation is because if you look in a bookmark you can see
atroni [7]3 years ago
4 0

\text{Hello there!}\\\\\text{Lets see if the rate of change for the two functions are the same}\\\\\text{We know that the rate of change for the first function is -2/3}\\\text{Lets find the rate of change for the second function}\\\\\text{We will use}\,\,\frac{y2-y1}{x2-x1}\,\,\text{to find the rate of change}\\\\\text{Plug in the coordinates:}\\\\\frac{3-5}{3-0}\\\\\text{Solve:}\\\\\frac{3-5}{3-0}\\\\\frac{-2}{3} = \text{rate of change for function 2}\\

\text{The rate of change is the same for both functions}\\\\\text{This means that:}\\\\\large\boxed{\text{Answer: C. Function 1 and Function 2 have the same rate of change.}}

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(9^6 * 7^-9)^-4.<br> Thanks!
Anuta_ua [19.1K]

Answer:

\frac{7^{36}}{9^{24}}

Step-by-step explanation:

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7 0
1 year ago
Under certain conditions, the number of bacteria present in a colony is approximated by f(t) = Age 0.023t, where t is in minutes
AleksandrR [38]

Answer:

  • 5 min: 3,029,058
  • 10 min: 3,398,220
  • 60 min: 10,732,234

Step-by-step explanation:

The given function is evaluated by substituting the given values of t. This requires using the exponential function of your calculator with a base of 'e'. Many calculators have that value built in, or have an e^x function (often associated with the Ln function).

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<h3>5 minutes</h3>

The number of bacteria present after 5 minutes is about ...

  f(5) = 2.7×10^6×e^(0.023×5) ≈ 3,029,058

<h3>10 minutes</h3>

The number of bacteria present after 10 minutes is about ...

  f(10) = 2.7×10^6×e^(0.023×10) ≈ 3,398,220

<h3>60 minutes</h3>

The number of bacteria present after 60 minutes is about ...

  f(60) = 2.7×10^6×e^(0.023×60) ≈ 10,732,234

8 0
2 years ago
Find the probability that a randomly selected group of five adults will contain all men. Give your answer as a reduced fraction.
Snowcat [4.5K]

Assuming the probability of selecting one man is 1/2 and independent events,

p = (\frac 1 2)^5 = \frac{1}{32}

Answer: 1/32

7 0
2 years ago
How do you round 2.8497 × 10^3 and 349.69 to 3 significant figures?
Kobotan [32]

Your answer for rounding 2.8497 x 10^3 is correct: 2.85 x 10^3.

350.0 is not correct because it has 4 sig figs. The proper rounding would be simply 350. with not additional zeros.

6 0
3 years ago
The number sentence 4*7 = (4*3)+ (4*4) is an example of what property
Mariulka [41]

This is Commutative property of addition

7 0
3 years ago
Read 2 more answers
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