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ozzi
3 years ago
9

Positive numbers are not closed under subtraction. Give an example of this 1 below.

Mathematics
1 answer:
vodka [1.7K]3 years ago
7 0

Answer:

5 -3 = 2

3-5 = -2

Step-by-step explanation:

In this question, we want to examine the validity of the statement by the use of an example.

Firstly, we need to understand the meaning of the fact that they are ‘closed’

By saying these numbers are closed under this arithmetic operation i.e subtraction, we directly mean that they obey the closure property.

Now, to obey the closure property means that if we move either way i.e by switching the numbers and performing the same arithmetic operation of subtraction, we are supposed to get same answer.

What this means in terms of examples is as follows;

Consider two positive numbers, 5 and 3

Now we know that 5-3 = 2

To check if the closure property is obeyed, switch the place of the numbers.

This means we would have;

3-5 = -2

We can see that both results are not the same. We can then conclude that the arithmetic operation of subtraction is not closed or does not obey the closure property for positive numbers.

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Answer:

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Part A)

100 meters.

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Step-by-step explanation:

The golf-ball hit by the Seven-Iron is modeled by the equation:

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And the ball hit by the Nine-Iron is modeled by the equation:

h=-0.004d^2+0.5d

Where <em>h</em> is the height of the ball after <em>d</em> meters.

When they are at the same height, the two equations will equal each other.

Graphically, this is where the two graphs will intersect.

To solve this using a Ti-84, you can follow these steps (I'm using the Ti-84 Plus Silver Edition):

1) Using [Y=], write and then [GRAPH] the two equations.

2) Press [ZOOM] and [ZOOM OUT] until you can see both graphs clearly.

3) To find the intersection point, press [2ND] and then [CALC] (above [TRACE]).

4) Choose [5) Intersect].

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6) When it asks you to guess, put the cursor to as close to the intersection point as possible. Ignore the intersection at the origin point.

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Therefore, the intersection point (not counting (0,0)) is at (100, 10).

Therefore, the ball will reach the same height of 10 meters after 100 meters.

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