All categories

4 years ago

What is the area of this trapezoid Will mark brainless to right answer and give thanks

Mathematics

1 answer:

aksik [14]4 years ago

4 0

Answer:

Step-by-step explanation:

area of trapezoid is given by formula

Area = $\frac{a+b}{2}$ h

where a is one base, b is another base and h is height

In given case, we have

a= 7+7+3 = 17

b= 3

h= 8

Substituting the values

Area= $\frac{17+3}{2}$ x 8

= $\frac{20}{2}$ x 8

= 10 x 8

= 80

You might be interested in

15pts awarded and brainliest will be chosen!!!!!

True [87]

Answer: OPTION B

Step-by-step explanation:

Let be "x" the acceptable lengths for the rod.

You know that the ideal length of the metal rod is 30.5 centimeters and the measured length may vary from the ideal length by at most 0.015 centimeters.

Therefore, knowing this, you can say that the acceptable lengths must be:

$30.5cm-0.015cm\leq x\\\\30.485\leq x$

$x \leq 30.5cm+0.015cm\\\\x\leq 30.515$

Therefore, the range of acceptable lengths for the rod is the following:

$30.485\leq x\leq 30.515$

This range matches with the one shown in the option B.

5 0

3 years ago

1/3 times 1/4 a,1/12 b,1/16 c,1/7 or d, 1/2

Ostrovityanka [42]

Answer:

a,1/12

Step-by-step explanation:

6 0

3 years ago

Do you think you now the answer comment it down

Veseljchak [2.6K]

Answer:

1 = true

2 = false

3 = false

4 = false

4 0

2 years ago

Read 2 more answers

Simplify please. Picture is attached

dem82 [27]

$\dfrac{2 \sqrt{3} }{3 \sqrt{5} } = \dfrac{ \sqrt{4} \times \sqrt{3} }{ \sqrt{9} \times \sqrt{5} } = \dfrac{ \sqrt{4} }{ \sqrt{15} } = \dfrac{2 \sqrt{15} }{15}$

3 0

3 years ago

Write an equation for a circle with a diameter that has endpoints at (7, –4) and (1, –10). Round to the nearest tenth if necessa

Black_prince [1.1K]

The standard form for the equation of a circle is :

(x−h)^2+(y−k)^2=r2 ----------- EQ(1)
where handk are the x and y coordinates of the center of the circle and r is the radius.
The center of the circle is the midpoint of the diameter.

So the midpoint of the diameter with endpoints at (7,-4)and(1,-10) is :

((7+(1))/2,(-4+(-10))/2)=(4,-7)

So the point (4,-7) is the center of the circle.

Now, use the distance formula to find the radius of the circle:

r^2=(7−(4))^2+(-4−(-7))^2=9+9=18

⇒r=√18

Subtituting h=4, k=-7 and r=√18 into EQ(1) gives :

(x-4)^2+(y+7)^2=18

7 0

3 years ago