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andrezito [222]

3 years ago

6

The rate of change of atmospheric pressure P with respect to altitude h is proportional to P, provided that the temperature is c

onstant. At a specific temperature the pressure is 102 kPa at sea level and 87.7 kPa at h = 1,000 m. (Round your answers to one decimal place.)
(a) What is the pressure at an altitude of 4000 m?
kPa
(b) What is the pressure at the top of a mountain that is 6463 m high?
kPa

1 answer:

Valentin [98]3 years ago

4 0

Answer:

idk this is actually hard

Step-by-step explanation:

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Find the value of the variable such that: the value of 5−a is 20 greater than the value of 6a−1

vovangra [49]

Answer:

-2

Step-by-step explanation:

(5 - a) = 20 + (6a -1) . . . . . 5-a is 20 greater than 6a-1

5 = 7a +19 . . . . . . . . . . . . . add a, collect terms

-14 = 7a . . . . . . . . . . . . . . . subtract 19

-2 = a . . . . . . . . . . . . . . . . divide by 7

The value of the variable is -2.

_____

<u>Check</u>

5 - (-2) = 7

6(-2) -1 = -13

7 is 20 greater than -13, so the answer checks OK.

4 0

3 years ago

1. Find the length of AB if A is (3,6) and B is (-3,2)

In-s [12.5K]

Answer:

Step-by-step explanation: In isosceles triangle ABC, AB = BC.(2) Bob does his homework if and only if George gets candy.What is the length, to the nearest tenth, of the line segment joining 1.25000. (3) 151.9. (-4-146)2+(2-5272. 6. What is the slope of a line perpendicular to the line whose MLABC = (2x+10), find mLACB. C. rectangular box has a base that is a rectangle with are 10 and 6, find the height of the trapezoid. c) 6. 8) In triangle ABC, the measure of angle A is 60 degrees. If the measure of angle B is 12) Square ABCD, above, has coordinates: C(-2, 2) and D(-2, -2).

Hope this helped!

5 0

3 years ago

Read 2 more answers

16. Sarina throws a ball up into the air, and it falls on the ground nearby. The ball's height, in feet, is modeled by the funct

tia_tia [17]

Answer:

Step-by-step explanation:

7 0

3 years ago

PLEAZZZZZZZZZZ HELP ASAP

stich3 [128]

QUESTION 1

GIVEN:

$long \: base = 3 \times (short \: base)$

$height = (short \: base) - 2$

$area = 30 {in}^{2}$

IMPORTANT EQUATIONS

$trapezoid \: area = \frac{sum \: of \: bases}{2} \times height$

SOLVE:

$30 = \frac{short + long}{2} (short - 2)$
$30 = \frac{(short + 3short)}{2} \times (short - 2)$

$30 = \frac{4short}{2} (short - 2)$

$30 = 2{(short)}^{2} - 4(short)$

${short}^{2} - 2(short) - 15 = 0$

factor:

$(short - 5)(short + 3) = 0$

$short = 3 \: and \: - 5$
Negative five is not a reasonable answer, so we focus on the positive three and say that is the length of the short base.

so, the answers:

$short \: base = 3 \: in$

$long \: base = 3 \times 3 = 9 \: in$

$height = 3 - 2 = 1 \: in$

QUESTION 2

GIVEN
convert 3ft to inches.

$l = 32 + w$

$area = lw = 130 {in}^{2}$
or

$w = \frac{130}{l}$

substitute

$l = 32 + \frac{130}{l}$

solve for l:

${l}^{2} - 32 l- 130 = 0$
QUESTION 3

$x(x + 2) = 80$

solve for X

${x}^{2} + 2x - 80 = 0$
$(x - 10)(x + 8) = 0$

$x = 10 \: and \: - 8$

take the positive value since it's the only one that makes sense in this context.

so the two values are:

$10 \: and \: 8$

8 0

3 years ago

Jamaar Tannock is thinking about buying his first car. He is looking at a car with an average retail value of $2,500. It has a r

DiKsa [7]

Answer:

$2,300 is the average retail price.

Step-by-step explanation:

$2500 is the initial price.

$100 is added to the price due to a radio.

$2500 + $100 = $2,600.

$300 is deducted due to mileage.

$2,600 - $300 = 2,300

8 0

3 years ago