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Inessa [10]
3 years ago
15

Professors at a local university earn an average salary of $80,000 with a standard deviation of $6,000. The salary distribution

cannot be regarded as bell-shaped. What can be said about the percentage of salaries that are less than $68,000 or more than $92,000?
a. It is at least 75 percent.
b. It is at least 55 percent.
c. It is at least 25 percent.
d. It is at most 25 percent.
Mathematics
1 answer:
Sladkaya [172]3 years ago
7 0

Answer:

d. It is at most 25 percent.

Step-by-step explanation:

According to Chebyshev's inequality, for a given number of standard deviations, k, no more than 1/k² can be more than k standard deviations from the mean. In this situation the amount of standard deviations from the mean of the upper and lower bound of salaries are:

U=\frac{\$92,000-\$80,000}{\$6,000}=2\\L = \frac{\$80,000-\$68,000}{\$6,000}= 2

For k = 2, applying Chebyshev's inequality:

P( \$68,000 \leq X \leq \$92,000)= \frac{1}{2^2} = 0.25

Therefore, at most 25% of the salaries are less than $68,000 or more than $92,000.

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Answer:

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Step-by-step explanation:

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First, get rid of the denominator by multiplying both sides by 2:

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Add both sides by 6 then subtract both sides by x:

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2 years ago
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Sammy buys 5 pounds of oranges for 7.50 at this rate how much would 8 pounds of oranges cost
Nadusha1986 [10]

The cost of 8 pounds of oranges based on the total cost of 5 pounds bought is 12.00

What is the cost for a pound of oranges?

The cost of a pound of oranges based on the rate at which 5 pounds were bought and 8 pounds would also be bought is determined as the amount paid for 5 pounds of oranges divided by the number of pounds of oranges bought

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Find out more about unit cost on:brainly.com/question/17430583

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3 0
1 year ago
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jeyben [28]
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yuradex [85]
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