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Inessa [10]
3 years ago
15

Professors at a local university earn an average salary of $80,000 with a standard deviation of $6,000. The salary distribution

cannot be regarded as bell-shaped. What can be said about the percentage of salaries that are less than $68,000 or more than $92,000?
a. It is at least 75 percent.
b. It is at least 55 percent.
c. It is at least 25 percent.
d. It is at most 25 percent.
Mathematics
1 answer:
Sladkaya [172]3 years ago
7 0

Answer:

d. It is at most 25 percent.

Step-by-step explanation:

According to Chebyshev's inequality, for a given number of standard deviations, k, no more than 1/k² can be more than k standard deviations from the mean. In this situation the amount of standard deviations from the mean of the upper and lower bound of salaries are:

U=\frac{\$92,000-\$80,000}{\$6,000}=2\\L = \frac{\$80,000-\$68,000}{\$6,000}= 2

For k = 2, applying Chebyshev's inequality:

P( \$68,000 \leq X \leq \$92,000)= \frac{1}{2^2} = 0.25

Therefore, at most 25% of the salaries are less than $68,000 or more than $92,000.

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There are several ways two triangles can be congruent.

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1.\ \mathbf{AO = DO} --- Because O is the midpoint of line segment AD

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3.\ \mathbf{\angle AOB =\angle COD} ---- Because vertical angles are congruent

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Using corresponding theorem,

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