I graphed the vertices and got a triangle but its very hard to solve its perimeter. Therefore, I identified right triangles to help me solve for the perimeter making each side the hypotenuse of each right triangle. Pythagorean Theorem: a² + b² = c² a = short leg ; b = long leg ; c = hypotenuse
P(0,0) ; R(-3,4) a = 3 ; b = 4 ; 3² + 4² = c² 9 + 16 = c² 25 = c² √25 = √c² 5 = c
P(0,0) ; Q(8,6) a = 6 ; b = 8 6² + 8² = c² 36 + 64 = c² 100 = c² √100 = √c² 10 = c
Q(8,6) ; R(-3,4) a = 2 ; b = 11 2² + 11² = c² 4 + 121 = c² 125 = c² √125 = √c² 11.18 = c
