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3 years ago

Help with this please

Mathematics

1 answer:

AysviL [449]3 years ago

6 0

A) The x-axis represents minutes used per month. The y-axis represents cost in dollars. Following the line of the graph indicating 60 minutes per month it shows Plan A costs $6 per month while Plan B costs $12 per month.

Plan A is cheaper.

Difference in prices = cost of Plan B for 60 minutes per month - cost of Plan A for 60 minutes per month

= 12 - 6 = $6 per month

b) To solve, identify where the lines of Plan A and Plan B intersect. Both lines intersect at 160 minutes per month.

Which plan costs less when less minutes are used? To solve, identify which line has a lower cost on the y-axis. Plan A costs less if less than 160 minutes are used.

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Answer: a) $\dfrac{3}{874}$

b) $\dfrac{30}{3059}$

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Step-by-step explanation:

Given : Number of students : 11

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Total persons : $11+13=24$

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$^{11}C_{6}=\dfrac{11!}{6!(11-6)!}=462$

Then , the probability of selecting a jury of all students :-

$\dfrac{462}{134596}=\dfrac{3}{874}$

b) Number of ways of selecting a jury of all faculty :-

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Then , the probability of selecting a jury of all students :-

$\dfrac{1716}{134596}=\dfrac{30}{3059}$

c) Number of ways of selecting a jury of two students and four faculty :-

$^{11}C_{2}\times^{13}C_{4}=\dfrac{11!}{2!(11-2)!}\times\dfrac{13!}{4!(13-4)!}=39325$

Then , the probability of selecting a jury of all students :-

$\dfrac{39325}{134596}=\dfrac{3575}{12236}$

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