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Julli [10]
3 years ago
11

suzanne buys 6 paints sets. each set contains the same number of brushes. she buys 18 brushes.how many bruxhes are in each paint

set?
Mathematics
2 answers:
KIM [24]3 years ago
8 0
So we know that there are 6 sets, and there is an equal number of 18 brushes in each set. This is simple maths: 6/18 which is 3. So each set has 3 bushes, so if we have 6 sets (3 x 6) = 18.

Ans = 3
Luda [366]3 years ago
6 0
3 bruches i think

Because you need to divide
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Liz drops a marable from the top of a cliff 96 feet off the ground. The height of the marable is described by the quadratic equa
ZanzabumX [31]

Step-by-step explanation:

quadratic equation??

h=-16+2+96

t is not mentioned

7 0
4 years ago
weekly wages at a certain factory are normally distributed with a mean of $400 and a standard deviation of $50. find the probabi
kenny6666 [7]

Answer:

0.34134

Step-by-step explanation:

In other to solve for this question, we would be using the z score formula

z = (x - μ) / σ

x = raw score

μ = mean

σ = Standard deviation

We are told in the question to find the probability that a worker selected at random makes between $350 and $400

let x1 = 350 and x2= 400 with the mean μ = 400 and standard deviation σ = $50.

z1 = (x1 - μ) / σ = (350-400) / 50 = -1

z2 = (x2 - μ) / σ = (400 - 400) / 50 = (0/50) = 0

From tables, P(z <= -1) = 0.15866

P(z <= 0) = 0.5

Then, the probability would give us, P(-1 ≤ z ≤ 0) =0.5 - 0.15866 =

0.34134

Hence, The probability that a worker selected at random makes between $350 and $400 = 0.34134

7 0
3 years ago
when deciding how much money to set aside for a new car, a good rule of thumb to follow is to budget about one-fifth of your mon
joja [24]
3750(0.20)=$750
1/5 as a percent is 20% and as a fraction it is 0.20
5 0
3 years ago
A person invests $4000 at 2% interest compounded annually for 4 years and then invests the balance (the $4000 plus the interest
faltersainse [42]
\bf \qquad \textit{Compound Interest Earned Amount}&#10;\\\\&#10;A=P\left(1+\frac{r}{n}\right)^{nt}&#10;\quad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;P=\textit{original amount deposited}\to &\$4000\\&#10;r=rate\to 2\%\to \frac{2}{100}\to &0.02\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{annually, thus once}&#10;\end{array}\to &1\\&#10;t=years\to &4&#10;\end{cases}&#10;\\\\\\&#10;A=4000\left(1+\frac{0.02}{1}\right)^{1\cdot 4}\implies A=4000(1.02)^4\implies A\approx 4329.73

then she turns around and grabs those 4329.73 and put them in an account getting 8% APR I assume, so is annual compounding, for 7 years.

\bf \qquad \textit{Compound Interest Earned Amount}&#10;\\\\&#10;A=P\left(1+\frac{r}{n}\right)^{nt}&#10;\quad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;P=\textit{original amount deposited}\to &\$4329.73\\&#10;r=rate\to 8\%\to \frac{8}{100}\to &0.08\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{annually, thus once}&#10;\end{array}\to &1\\&#10;t=years\to &7&#10;\end{cases}&#10;\\\\\\&#10;A=4329.73\left(1+\frac{0.08}{1}\right)^{1\cdot 7}\implies A=4329.73(1.08)^7\\\\\\ A\approx 7420.396

add both amounts, and that's her investment for the 11 years.
7 0
3 years ago
I need help to these questions. Convert these fractions to a decimal 7/8 , 4 3/8. Thanks
ehidna [41]
Simple...

you have: \frac{7}{8} and 4 \frac{3}{8}

Now, the first one is easy just divide it...

\frac{7}{8} =0.875

Now....

4 \frac{3}{8}    needs to be converted...

Multiply the whole number*denominator...

4*8=32

Now add the numerator....

32+3=35

Now use the original denominator...

\frac{35}{8}

Now divide...

\frac{35}{8}=4.375&#10;

Thus, your answer.
7 0
3 years ago
Read 2 more answers
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