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8090 [49]
3 years ago
15

weekly wages at a certain factory are normally distributed with a mean of $400 and a standard deviation of $50. find the probabi

lity that a worker selected at random makes between $350 and $400.
Mathematics
1 answer:
kenny6666 [7]3 years ago
7 0

Answer:

0.34134

Step-by-step explanation:

In other to solve for this question, we would be using the z score formula

z = (x - μ) / σ

x = raw score

μ = mean

σ = Standard deviation

We are told in the question to find the probability that a worker selected at random makes between $350 and $400

let x1 = 350 and x2= 400 with the mean μ = 400 and standard deviation σ = $50.

z1 = (x1 - μ) / σ = (350-400) / 50 = -1

z2 = (x2 - μ) / σ = (400 - 400) / 50 = (0/50) = 0

From tables, P(z <= -1) = 0.15866

P(z <= 0) = 0.5

Then, the probability would give us, P(-1 ≤ z ≤ 0) =0.5 - 0.15866 =

0.34134

Hence, The probability that a worker selected at random makes between $350 and $400 = 0.34134

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Marie would pay $1.50 because 200 grams is .2 Kg and you would multiply 7.50 by .2 and you'd get your answer
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In AQRS, m2 Q = 63º, mZ R = 70°, and m2 S= 47°. Which side of AQRS is the
8090 [49]

Answer:

D. QR.

Step-by-step explanation:

1) in ΔQRS the side QR is opposite the angle S (47°); QS is opposite the angle R (70°); RS is opposite the angle Q (63°);

2) the rule is: greater angle is opposite the longer side;

3) according to the rule the angle 'S' is the smallest, then the side QR is the shortest.

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3 years ago
A water tank is in the shape of a right circular cylinder with a height of 20 feet and a volume 320π of cubic feet. What is the
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To solve for radius use the volume formula and solve for r.

V = πr²h
320π = πr²(20)
320π/π = 20r²
320 = 20r²
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16 = r²
√16 = r
4 = r

Answer is D. 4 feet.

Hope this helps :)

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3 years ago
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A box of candy had 4 cherry pieces for every 9 lemon pieces. If the box had 45 lemon pieces, how many cherry pieces would there
Damm [24]

Answer:

20

Step-by-step explanation:

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B9%7Dx%20-%20%5Cfrac%7B1%7D%7B3%7D%20%3D%20-1" id="TexFormula1" title="\frac{2
egoroff_w [7]

\large \mathfrak{Solution : }

let's solve for x :

  • \dfrac{2}{9} x -  \dfrac{1}{3}  =  - 1

  • \dfrac{2}{9}  x =  - 1 +  \dfrac{1}{3}

  • \dfrac{2}{9} x =  \dfrac{ - 3 + 1}{3}

  • x =  \dfrac{ - 2}{3}  \times  \dfrac{9}{2}

  • x =  - 3

I hope it helped...

7 0
3 years ago
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