Answer:
It is arithmetic and it has a common difference of -99
Multiples communes de 6 y 9 son 18 y 36
Answer:
Step-by-step explanation:
Problem A
t(1) = 2(1) + 5
t(2) = 2*2 + 5 = 9
t(3) = 2*3 + 5 = 11
t(4) = 2*4 + 5 = 13
So this is the explicit result. Now try it recursively.
t_3 = t_2 + 2
t_3 = 9 + 2
t_3 = 11 which is just what it should do.
t_n = t_(n - 1) + 2
Problem B
t(1) = 3 * 1/2
t(1) = 3/2
t(2) = 3*(1/2)^2
t(2) = 3 * 1/4
t(2) = 3/4
t(3) = 3*(1/2)^3
t(3) = 3 * 1/8
t(3) = 3/8
t(4) = 3 (1/2)^4
t(4) = 3 (1/16)
t(4) = 3/16
So in general
t_n = t_n-1 * 1/2
For example t(5)
t_5 = t_4 * 1/2
t_5 = 3 /16 * 1/2 = 3/32
Answer:
Step-by-step explanation:
I've enclosed a graph to show you that there is one solution.
-4x + 3y = - 12
<u>- 2x + 3y = - 18</u><em><u> </u></em><em> </em>Subtract
-2x = 6 Divide by - 2
-2x/-2 = 6/-2
x = - 3
- 4x + 3y = - 12
-4(-3) + 3y = - 12
12 + 3y = - 12
3y = - 12 - 12
3y = - 24
3y/3 = - 24/3
y = - 8
Which is exactly what the graph shows.
You can tell immediately that this has 1 or more solutions just by looking at the number in front of x and y in each each equation.
It's always a good idea to graph a question like this one. Desmos is a pretty good tool to use if you don't have a graphing calculator.
The y's are the same so you are 1/2 way home in saying what you did.
The x's are different so that means you have at least 1 solution.
I believe you would calculate this like so;
We want 18% less than 100% of that amount therefore the single multiplier we would use is as follows:
(100% - 18%) = 82%
Which alternatively = 0.82
Does that make sense? If not I can explain it a bit more. Please let me know.