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Blababa [14]
4 years ago
14

Describe all situation where vertical angles are also supplementary

Mathematics
2 answers:
timofeeve [1]4 years ago
6 0

Answer:

if  vertical angles are right angles  then the angles are supplementary.

Step-by-step explanation:

Vertical angles: When two lines are intersect to each other then the opposite angles made at the point of intersection are called vertical angles.

Vertical angles are always equal in measurement.

Supplementary angles: The angles whose sum is 180 degrees are called supplementary angle.

Let x and y are vertical angles

Then, x=y

If angles x and y are supplementary

x+y=180^{\circ}

x+x=180^{\circ}

2x=180^{\circ}

x=\frac{180}{2}=90^{\circ}

x=y=90^{\circ}

When x and y=90 degrees then the angle x and y are supplementary.

Therefore, we can say that if vertical angles are right angles  then the angles are supplementary.

Nataly_w [17]4 years ago
3 0
Vertical angles are always the same size. if they are supplementary the measures must add to 180. 180/2=90. vertical angles are supplementary only when they are right angles, our 90°
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3 years ago
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Using the hypergeometric distribution, it is found that there is a 0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.

In this problem, the bulbs are chosen without replacement, hence the <em>hypergeometric distribution</em> is used to solve this question.

<h3>What is the hypergeometric distribution formula?</h3>

The formula is:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

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  • N is the size of the population.
  • n is the size of the sample.
  • k is the total number of desired outcomes.

In this problem:

  • There are 12 bulbs, hence N = 12.
  • 3 are defective, hence k = 3.

The third defective bulb is the fifth bulb if:

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Hence:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

P(X = 2) = h(2,12,4,3) = \frac{C_{3,2}C_{9,1}}{C_{12,4}} = 0.2182

0.2182 x 1/8 = 0.0273.

0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.

More can be learned about the hypergeometric distribution at brainly.com/question/24826394

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2 years ago
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Answer:

In the first box, put 24y

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Step-by-step explanation:

3y x 8 = 25y

8 x 2 = 16

<em>Hope that helps! :)</em>

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Answer:

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