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stealth61 [152]
4 years ago
9

Please Solve Quickly & Show Work!! Please Hurry I'm Offering 15pts PLEASE BE ACCURATE

Mathematics
2 answers:
natta225 [31]4 years ago
4 0
-----------------------------------

allochka39001 [22]4 years ago
3 0
The solution can be anywhere where it is shaded both black and red.

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Solve the question! 2y/3+5=20​
klasskru [66]

Answer:

2y=20*8

2y=160

y=160/2

y=80

6 0
3 years ago
Find the range of the data. Scores: 81, 79, 80, 88, 72, 96, 86, 73, 79, 88 A) 22
Igoryamba
Order: 96,88,88,86,81,80,79,79,73,72
96-72= 24
B.)24
4 0
3 years ago
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If a number is odd, then it has a remainder of 1 when divided by 2.
kherson [118]

Answer:

The hypothesis of the conditional is "<em>A number is odd</em>".

Step-by-step explanation:

The statement can be represented by the following proposition:

P \implies Q (Eq. 1)

Where:

P is the hypothesis of the proposition.

Q is the conclusion of the proposition.

\implies - Binary connector, which means "If...., then...."

In this case, we present what each propostion represents:

P = A number is odd.

Q = It has a remainder of 1 when divided by 2.

In consequence, the hypothesis of the conditional is "<em>A number is odd</em>".

6 0
4 years ago
Solving Exponential and Logarithmic Equation In exercise,solve for x or t.See example 5 and 6.
Amanda [17]

Answer:

t=\frac{ln 3}{12ln(1 +\frac{0.07}{12})}

t=15.74

Step-by-step explanation:

( 1 + 0.07/12)^{12t} = 3

Take ln on both sides

ln(( 1 +\frac{0.07}{12})=ln 3

move the exponent 12t before ln as per log property

12tln(1 +\frac{0.07}{12})=ln 3

now divide the ln on both sides to make 12t alone

12t=\frac{ln 3}{ln(1 +\frac{0.07}{12})}

divide both sides on both sides

t=\frac{ln 3}{12ln(1 +\frac{0.07}{12})}

t=15.74

5 0
3 years ago
Which represents the inverse of the function f(x) = 4x?
Licemer1 [7]

Answer:

The inverse is 1/4x

Step-by-step explanation:

y = 4x

To find the inverse, exchange x and y

x = 4y

Solve for y

1/4 x = 4y/4

1/4x = y

The inverse is 1/4x = y

3 0
3 years ago
Read 2 more answers
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