Solve 1/2cot(x)>=1/2 over 0<=x<=2pi
1 answer:
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Answer:
(0, π/4] ∪ (π, 5π/4]
Step-by-step explanation:
Multiplying by 2 gives ...
cot(x) ≥ 1
The cotangent function decreases from ∞ to 1 in the domain (0, π/4], and again in the domain (π, 5π/4]. The solution is the union of these two intervals.
x ∈ (0, π/4] ∪ (π, 5π/4]
_____
(a, b] is interval notation for a < x ≤ b
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Answer:
is the required equation.
Therefore, the second option is true.
Step-by-step explanation:
We know that the slope-intercept form of the line equation of a linear function is given by
where m is the slope and b is the y-intercept
Taking two points (0, -2) and (1, 0) from the table to determine the slope using the formula
substituting the point (0, -2) and the slope m=2 in the slope-intercept form to determine the y-intercept i.e. 'b'.
Now, substituting the values of m=2 and b=-2 in the slope-intercept form to determine the equation of a linear function
Thus, is the required equation.
Therefore, the second option is true.
You have sqrt(8), sqrt(18), and sqrt(2).
You need to simplify the radicals.
sqrt(2) is already simplified.
For both sqrt(8) and sqrt(18), you need to factor out the greatest perfect square.
8 = 4 * 2
You can take the square root of 4 and put it outside the root.
18 = 9 * 2
You can take the square root of 9 and put it outside the root.
You need to simplify the radicals.
sqrt(2) is already simplified.
For both sqrt(8) and sqrt(18), you need to factor out the greatest perfect square.
8 = 4 * 2
You can take the square root of 4 and put it outside the root.
18 = 9 * 2
You can take the square root of 9 and put it outside the root.