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patriot [66]
3 years ago
14

Solve 1/2cot(x)>=1/2 over 0<=x<=2pi

Mathematics
1 answer:
RSB [31]3 years ago
3 0

9514 1404 393

Answer:

  (0, π/4] ∪ (π, 5π/4]

Step-by-step explanation:

Multiplying by 2 gives ...

  cot(x) ≥ 1

The cotangent function decreases from ∞ to 1 in the domain (0, π/4], and again in the domain (π, 5π/4]. The solution is the union of these two intervals.

  x ∈ (0, π/4] ∪ (π, 5π/4]

_____

(a, b] is interval notation for a < x ≤ b

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Vladimir [108]

z° = 80° (Being corresponding angles)

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3 years ago
Which function represents a reflection of f(x) = 5(0.8)x across the x-axis?
lukranit [14]

The function represents a reflection of f(x) = 5(0.8)x across the x-axis is f(x) = -5(0.8)^x

<h3>Reflection of functions and coordinates</h3>

Images that are reflected are mirror images of each other. When a point is reflected across the line y = x, the x-coordinates and y-coordinates change their position. In a similar manner, when a point is reflected across the line y = -x, the coordinates <u>changes position but are negated.</u>

Given the exponential function below

f(x) = 5(0.8)^x

If the function f(x) is reflected over the x-axis, the resulting function will be

-f(x)

This means that we are going to negate the function f(x) as shown;

f(x) = -5(0.8)^x

Hence the function represents a reflection of f(x) = 5(0.8)x across the x-axis is f(x) = -5(0.8)^x

Learn more on reflection here: brainly.com/question/1908648

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Answer:

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