Solve 1/2cot(x)>=1/2 over 0<=x<=2pi
1 answer:
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Answer:
(0, π/4] ∪ (π, 5π/4]
Step-by-step explanation:
Multiplying by 2 gives ...
cot(x) ≥ 1
The cotangent function decreases from ∞ to 1 in the domain (0, π/4], and again in the domain (π, 5π/4]. The solution is the union of these two intervals.
x ∈ (0, π/4] ∪ (π, 5π/4]
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(a, b] is interval notation for a < x ≤ b
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Answer:
find the value of x that makes the denominator zero: x = 7
Step-by-step explanation:
A vertical asymptote shows up where the denominator is zero. As the denominator gets closer to zero, the function value gets larger without bound (unless there is a numerator factor that cancels the one in the denominator).
To find the value of x at the vertical asymptote, solve the equation ...
denominator = 0
x - 7 = 0
x = 7 . . . . . . . add 7 to both sides
