x - 3y = 6 and x + y = 110 represents the system of equations used to find x, the number of CDs she sold last week, and y, the number of CDs she sold this week
number of CDs Kitts sold last week "x" is 84 and number of CDs she sold this week "y" is 26
<h3><u>
Solution:</u></h3>
Let "x" be the number of CDs Kitts sold last week
Let "y" be the number of CDs she sold this week
<em><u>Given that Last week she sold 6 more than 3 times the number of CDs that she sold this week</u></em>
Number of CDs Kitts sold last week = 6 + 3(number of CDs that she sold this week)
x = 6 + 3y ----- eqn 1
x - 3y = 6 ------- eqn 2
<em><u>Given that Ms. Kitts sold a total of 110 CDs over the 2 weeks</u></em>
Number of CDs Kitts sold last week + number of CDs she sold this week = 110
x + y = 110 ----- eqn 3
Thus eqn 2 and eqn 3 represents the system of equations used to find x, the number of CDs she sold last week, and y, the number of CDs she sold this week
<em><u>Let us solve the above equations to find values of "x" and "y"</u></em>
Substitute eqn 1 in eqn 3
6 + 3y + y = 110
6 + 4y = 110
4y = 104
<h3>y = 26</h3>
From eqn 3,
x + 26 = 110
x = 110 - 26 = 84
<h3>x = 84</h3>
Thus number of CDs Kitts sold last week = x = 84
Number of CDs she sold this week = y = 26
