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Stells [14]
3 years ago
12

What all the multiples of 8?

Mathematics
2 answers:
Rzqust [24]3 years ago
4 0
8,16,24,32,40,48,56,64,72,80
Gwar [14]3 years ago
3 0

Answer:

through 12?

Step-by-step explanation:

8,16,24,32,40,48,56,64,72,80,88,96

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Jim lost $55 in the stock market on seven consecutive days. How much money did Jim lose in all?
earnstyle [38]
I think he lost $375 because I'm pretty sure your supposed to multiply 55 and 7
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2 years ago
A jeweler buys gold jewelry and resells the gold to a refinery. The jeweler buys gold for $1,235.55 per ounce, and then resells
Naddika [18.5K]

Answer:

The correct answer is $.

The question states that the jeweler bought and sold 73.5 ounces of gold, so all we need to do is multiply the price of buying and selling one ounce of gold by 73.5.

Buying - $1235.55 per ounce

Selling - $1376.44 per ounce

73.5 x 1235.55 = 90,812.93

73.5 ounces of gold cost $90,812.93.

73.5 x 1376.44 = 101,168.34

73.5 ounces of gold can be sold for $101,168.34.

Now, all we have to do is subtract the amount spent on the gold from the amount of money made in order to find the profit. This is because the amount of money the jeweler makes depends on how much more money they made by selling the gold than buying it.

$101,168.34 - $90,812.93 = $10,355.41

The jeweler made $10,355.41 by buying and reselling 73.5 ounces of gold.

5 0
3 years ago
Read 2 more answers
George cut 5 oranges into quarters. How many slices of oranges did he have?
krek1111 [17]

Answer:

20 slices

Step-by-step explanation:

4 0
3 years ago
5. Can someone explain how to solve this?
zhannawk [14.2K]

Answer:

AC = 5 cm

BD = 12.5 cm (3 sf) [or 2 × root 39]

BE = 6.93 cm (3 sf) [or 4 × root 3]

Step-by-step explanation:

CE = 8cm [CE is radius of circle]

AC + 3 = 8

<u>A</u><u>C</u><u> </u><u>=</u><u> </u><u>5</u><u> </u><u>c</u><u>m</u>

BC = 8cm [BC is a radius of circle]

(AC)^2 + (AB)^2 = (BC)^2 [Pythagoras theorem]

25 + (AB)^2 = 64

AB = 6.2450 cm (5 sf) [or root 39]

BD = 2(BA)

= 2(6.2450)

<u>B</u><u>D</u><u> </u><u>=</u><u> </u><u>1</u><u>2</u><u>.</u><u>5</u><u> </u><u>c</u><u>m</u><u> </u><u>(</u><u>3</u><u> </u><u>s</u><u>f</u><u>)</u><u> </u><u>[</u><u>o</u><u>r</u><u> </u><u>2</u><u> </u><u>×</u><u> </u><u>r</u><u>o</u><u>o</u><u>t</u><u> </u><u>3</u><u>9</u><u>]</u>

(BA)^2 + (AE)^2 = (BE)^2 [Pythagoras theorem]

39 + 9 = (BE)^2

<u>B</u><u>E</u><u> </u><u>=</u><u> </u><u>6</u><u>.</u><u>9</u><u>3</u><u> </u><u>c</u><u>m</u><u> </u><u>(</u><u>3</u><u> </u><u>s</u><u>f</u><u>)</u><u> </u><u>[</u><u>o</u><u>r</u><u> </u><u>4</u><u> </u><u>×</u><u> </u><u>r</u><u>o</u><u>o</u><u>t</u><u> </u><u>3</u><u>]</u>

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3 years ago
Graphing a line it’s equation in standard form
Pani-rosa [81]
What’s the question?
3 0
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