The answer is -a + b = 0
If she wants to solve <span>a system of linear equations by elimination and if one equation is unknown, one of the solutions in the unknown equation must be negative:
Known equation: a + b = 4
Unknown equation: -a + b = ?
We know that a = 2 and be = 2, thus:
</span>Unknown equation: -2 + 2 = 0
The general form of the equation is -a + b = 0
Let's check it out:
Known equation: a + b = 4
Unknown equation: -a + b = 0
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Add them up: 2b = 4
b = 4/2 = 2
a + b = 4
a = 4 - b
a = 4 - 2
a = 2
So, the second equation is correct.
The answer for this is both C and D
0 is greater than -3
and -1 is greater than -3
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Answer:
8. C) 24.2
9. A) 8.1
Step-by-step explanation:
8. The radius is shown as being 7.8 +4.3 = 12.1, so the diameter x is ...
d = 2r
x = 2(12.1) = 24.2
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9. The unknown leg (y) of the right triangle can be found from the Pythagorean theorem.
y² +11.7² = 12.5² . . . . . the radius is half the diameter
y = √(156.25 -136.89) = √19.36 = 4.4
Then the segment of interest is ...
x + y = 12.5
x = 12.5 -4.4 = 8.1
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Answer:
A
Answer:
x = 13
y = 9
Step-by-step explanation:
Since this is a square all the side lengths would be equal to each other
4x - 22 = 2x + 4
4x - 2x = 4 + 22
2x = 26 divide both sides by 2
x = 13
5y - 15 = 3x + 3
5y - 3x = 3 + 15
2y = 18 divide both sides by 2
y = 9