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Finger [1]
3 years ago
13

Factor the following statement: 4x2 + 8x

Mathematics
1 answer:
ipn [44]3 years ago
5 0
The answer is
4
x
2
−
8
x
4
x
2
-
8
x
Factor
4
x
4
x
out of
4
x
2
4
x
2
.
4
x
(
x
)
−
8
x
4
x
(
x
)
-
8
x
Factor
4
x
4
x
out of
−
8
x
-
8
x
.
4
x
(
x
)
+
4
x
(
−
2
)
4
x
(
x
)
+
4
x
(
-
2
)
Factor
4
x
4
x
out of
4
x
(
x
)
+
4
x
(
−
2
)
4
x
(
x
)
+
4
x
(
-
2
)
.
4
x
(
x
−
2
)

I tried my best to put them together
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3 years ago
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Alden paid to have some programs printed for the football game last weekend. The printing cost per program was 54 cents, and the
uranmaximum [27]

Answer:

300 programs

Step-by-step explanation:

Let’s work with cents to make this easier. We convert the $12 to cents, making 1200 cents

Let the number of copies Alden printed be x. His total printing cost would be x * 54 = 54x cents.

He sold at 75 cents each and still had left 100 copies. This means his total sale would be (x - 100)75

He lost $12 on the venture. This means his cost price minus his selling price is $12 since it’s a loss.

Computing this:

54x - 75(x - 100) = 1200

54x - 75x + 7500 = 1200

-21x = 1200 - 7500

-21x = -6,300

x = 6300/21 = 300 programs

4 0
3 years ago
A game consists of randomly choosing a bag (labelled 1, 2 or 3) out of a choice of 100, and then again randomly, picking a ball
Scorpion4ik [409]

Answer:

the answer is 112

Step-by-step explanation:

8 0
3 years ago
suppose that incomes of families in Newport Harbor are normally distributed with a mean of $750,000 and a standard deviation of
denis23 [38]

Answer: 0.345

Step-by-step explanation:

Given : The incomes of families in Newport Harbor are normally distributed with Mean : \mu=\$ 750,000 and Standard deviation : \sigma= $250,000

Samples size : n=4

Let x be the random variable that represents the incomes of families in Newport Harbor.

The z-statistic :-

z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}

For x= $800,000

z=\dfrac{800000-750000}{\dfrac{250000}{\sqrt{4}}}=0.4

By using the standard normal distribution table , we have

The probability that the average income of these 4 families exceeds $800,000 :-

P(x>80,000)=P(z>0.4)=1-P(z\leq0.4)\\\\=1-0.6554217=0.3445783\approx0.345

Hence, the probability that the average income of these 4 families exceeds $800,000 =0.345

6 0
4 years ago
A 100-inch board is cut into two pieces one peice is three times the length of the other find the length of the shorter peice
Masteriza [31]

Answer:

5 ?

Step-by-step explanation:

8 0
3 years ago
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