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Sliva [168]
3 years ago
13

Calculate the regression coefficients in the above table by hand, using the statistics below

Mathematics
1 answer:
Shtirlitz [24]3 years ago
7 0
The coefficients are three and 85
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Combine like terms and simplify 4r - 6 - 2r + 5
murzikaleks [220]
C. 10r-3


Because 2r+5=7, the minus 6 and 7 which gives you 1 then minus 4 and 1 witch is 3 then you do 10r-3 and it will get you to 2r+5=7 again. I hope this helped!
4 0
2 years ago
(02.01 LC) Simplify 4 over 7 ÷ 3 over negative 8. negative 32 over 21 negative 3 over 14 3 over 14 32 over 21
zhannawk [14.2K]

Answer:

(4/7)÷ (3/-8). Division of fractions is the same as multiplying their reciprocals. So (4/7) x (-8/3). Now multiply the numerators together and denominators together (make sure you only use the negative sign once). (4 x -8) / (7 x 3) = -32/21

4 0
3 years ago
( 3 x 2 ) ^ 4 x 3 ^ -3 / 2 ^ 3 x 3 =<br><br> Simplify the exponential expression
Korvikt [17]

Answer:

2

Step-by-step explanation:

\frac{(3*2)^4*3^{-3}}{2^3*3}

we start simplifying by removing the parenthesis

Multiply the exponents inside the the parenthesis

3^4  * 2^4

\frac{3^4*2^4*3^{-3}}{2^3*3}

Now we apply exponential property

a^m * a^n = a^ (m+n)

3^4 * 3^-3 = 3^ (4-3) = 3^1

3 or 3^1  are same

\frac{3^1*2^4}{2^3*3^1}

3^1 at the top and bottom so we cancel it out

\frac{2^4}{2^3}

we apply log property . a^m / a^n = a^m-n

Now subtract the exponents

2^(4-3) = 2^1 = 2



4 0
3 years ago
Find the coordinates of the point three tenths<br><br> of the way from A(-4, -8) to B(11, 7)
Leviafan [203]

let's first off take a peek at those values.

let's say the point with those coordinates is point C, so C is 3/10 of the way from A to B.

meaning, we take the segment AB and cut it in 10 equal pieces, AC takes 3 pieces, and CB takes 7 pieces, namely AC and CB are at a 3:7 ratio.


\bf ~~~~~~~~~~~~\textit{internal division of a line segment}&#10;\\\\\\&#10;A(-4,-8)\qquad B(11,7)\qquad&#10;\qquad \stackrel{\textit{ratio from A to B}}{3:7}&#10;\\\\\\&#10;\cfrac{A\underline{C}}{\underline{C} B} = \cfrac{3}{7}\implies \cfrac{A}{B} = \cfrac{3}{7}\implies 7A=3B\implies 7(-4,-8)=3(11,7)\\\\[-0.35em]&#10;~\dotfill\\\\&#10;C=\left(\frac{\textit{sum of "x" values}}{\textit{sum of ratios}}\quad ,\quad \frac{\textit{sum of "y" values}}{\textit{sum of ratios}}\right)\\\\[-0.35em]&#10;~\dotfill


\bf C=\left(\cfrac{(7\cdot -4)+(3\cdot 11)}{3+7}\quad ,\quad \cfrac{(7\cdot -8)+(3\cdot 7)}{3+7}\right)&#10;\\\\\\&#10;C=\left( \cfrac{-28+33}{10}~~,~~\cfrac{-56+21}{10} \right)\implies C=\left( \cfrac{5}{10}~~,~~\cfrac{-35}{10} \right)&#10;\\\\[-0.35em]&#10;\rule{34em}{0.25pt}\\\\&#10;~\hfill C=\left( \frac{1}{2}~,~-\frac{7}{2} \right)~\hfill

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kicyunya [14]
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