Answer:
Step-by-step explanation:
Let's look at simpler cases. If there was just one visit that would be 124. if there were two, each time he'd have to pay 124 so it's 124+124 = 248. So this is multiplication, because next would be three, which is 124+124+124 or 124 time 3.
In total then it's 124*14. You may usually use an x for multiplication, and if you do just keep in mind * can also be used. or, if something is inside of parenthesis like this 124(14) or (124)14. If you need help doing the multiplication let me know.
Answer:
12.85, 12.86, 12.87, 12.88, 12.89, 12.90, 12.91, 12.92, 12.93, and 12.94
Step-by-step explanation:
there is none
Answer:
Yes
Step-by-step explanation:
Answer:
(1-cos2A) /(1+cos2A) =tan²A
Proof:
We know that,
cos(A+B) =cosA.cosB-sinA.sinB
=>cos2A=cos(A+A)
=>cos2A=cosA.cosA - sinA.sinA
=>cos2A=cos²A-sin²A
=>cos2A=(cos²A-sin²A)/(cos²A+sin²A
Since {cos²A+sin²A=1}
Divide the numerator & the denominator by (cos²A) to get,
cos2A = {(cos²A-sin²A) ÷cos²A} / {(cos²A+sin²A) ÷cos²A}
cos2A ={(1-tan²A)/(1+tan²A)}
Then,
1-cos2A = 1-[{(1–tan²A)/(1+tan²A)}]
1-cos2A =(1+tan²A-1+tan²A)/(1+tan²A)
1-cos2A=(2tan²A)/(1+tan²A)
And now.......
1+cos2A=1+[{(1-tan²A)/(1+tan²A)}]
1+cos2A={1+tan²A+1-tan²A}/{1+tan²A}
1+cos2A=2/(1+tan²A)
So now,
(1-cos2A)/(1+cos2A)= {2tan²A/(1+tan²A)}÷{2/(1+tan²A)}
={(2tan²A)(1+tan²A)}÷{2(1+tan²A)}
=tan²A
Step-by-step explanation:
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Answers A,C, and D are equivalent to 3:1