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olya-2409 [2.1K]
4 years ago
13

Determine whether the given function is a solution to the given differential equation. y=cosx+x8​, d^2y/dx^2 + y = x^8 + 56x^6.

Mathematics
1 answer:
Ulleksa [173]4 years ago
4 0

The correct question is:

Determine whether the given function is a solution to the given differential equation. y = cosx + x^8; d²y/dx² + y = x^8 + 56x^6

Step-by-step explanation:

Given the differential equation

d²y/dx² + y = x^8 + 56x^6.

Suppose y = cosx + x^8 is a solution, then differentiating y twice, and adding it to itself, must give the value on the right hand side of the differential equation.

Let us differentiate y twice

y = cosx + x^8

dy/dx = -sinx + 8x^7

d²y/dx² = -cosx + 56x^6

Now,

d²y/dx² + y = -cosx + 56x^6 + cosx + x^8

= 56x^6 + x^8

Therefore,

d²y/dx² + y = x^8 + 56x^6

Which shows that y = cosx + x^8 is a solution to the differential equation.

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meriva

Given:

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To find:

1. The measure of arc BEA.

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3. The measure of ∠BAD

Solution:

1. The measure of arc of full circle is 360°.

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Subtract 116° from both sides.

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2. Using the tangent-chord angle theorem:

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Using the fact that it is supplementary to ∠CAB.

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Subtract 58° from both sides.

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