<u>Answer:</u>
16th term in sequence a(n) = -6+ (n-1) 3 is 39.
<u>Solution:</u>
Need to determine 16 terms in sequence.
a(n) = -6+3(n-1) that is = -6+ (n-1) 3
from given expression we can say that first term = -6 and common difference d = 3
And given expression = -6+ (n-1) 3 represents formula of nth term of an Arithmetic Sequence.
So substituting n = 16 in given formula we get
= -6+ (16-1) 3
=> = -6 + (15 x 3)
=> = -6 + 45
=> = 39
Hence 16th term in sequence = -6+ (n-1) 3 is 39.