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Lena [83]
4 years ago
10

Find the 16 term in sequence a(n) = -6+3(n-1)

Mathematics
2 answers:
Annette [7]4 years ago
7 0
39. A(16) = -6 + 3(16-1) = -6 + 45 = 39.
ira [324]4 years ago
5 0

<u>Answer:</u>

16th term in sequence a(n) = -6+ (n-1) 3 is 39.

<u>Solution:</u>

Need to determine 16 terms in sequence.

a(n) = -6+3(n-1) that is a_n = -6+ (n-1) 3

from given expression we can say that first term a_1 = -6 and common difference d = 3

And given expression a_n = -6+ (n-1) 3 represents formula of nth term of an Arithmetic Sequence.  

So substituting n = 16 in given formula we get  

a_{16} = -6+ (16-1) 3

=> a_{16} = -6 + (15 x 3)  

=> a_{16} = -6 + 45  

=> a_{16} = 39

Hence 16th term in sequence a_n = -6+ (n-1) 3 is 39.

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