A line has the equation x = -8 What is the equation of the line parallel to this line and going through the point, ( -3, -1 )?
1 answer:
X=-8 is just a vertical line 8 units to the left of the origin.
So a parallel line will also be vertical and as asked it must pass through (-3,-1) so it is:
x=-3
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A^2 - 6a/a-6 • a+3/a
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a • (a + 3)/a
a(a+3)/a
a+3.
The correct solution to this question would be B. a+3.
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