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PSYCHO15rus [73]
4 years ago
11

Which of the following terms measures the amount of matter in an object? Weight or mass

Chemistry
1 answer:
Oksanka [162]4 years ago
3 0
Mass measures the amount of matter in an object
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One crystalline form of silica (SiO2) has a cubic unit cell, and from X-ray diffraction data it is known that the cell edge leng
tigry1 [53]

Answer:

There are 8Si atoms and 16 O atoms per unit cell

Explanation:

From the question we are told that:

Edge length l=0.700nm=>0.7*10^9nm

Density \rho=2.32g/cm^3

Generally the equation for Volume is mathematically given by

V=l^3

V=(0.7*10^9)m^3

V=3,43*10^-{22}cm

Where

Molar mass of  (SiO2) for one formula unit

M=28+32

M=60g/mol

Therefore

Density of Si per unit length is

\rho_{si}=\frac{9.96*10^{23}}{3.43*10^22}

\rho=0.29

Molar mass of  (SiO2) for one formula unit

M=28+32

M=60g/mol

Therefore

There are 8Si atoms and 16 O atoms per unit cell

6 0
4 years ago
When a mixture of glucose 6-phosphate and fructose 6-phosphate is incubated with the enzyme phosphohexose isomerase, the final m
Anastasy [175]

Answer:

The correct option is B

Explanation:

The reaction is given as

             Glucose\ 6-phosphate ---->fractose \ 6-phosphate

The equilibrium constant for this reaction is mathematically represented as

               K_c = \frac{[concentration \ of  \ product ]}{concentration \ of  \ reactant } = \frac{[fructose \ 6 -phosphate]}{[Glucose \ 6 - phosphate]}

From the question we are told that

    [Glucose 6-phosphate] = 2 × [fructose 6-phosphate]

So  

      K_c  = \frac{[fructose \ 6 -phosphate]}{[2 (fructose \ 6 -phosphate)]} = 0.5

Generally change in free energy \Delta G is mathematically represented as

          \Delta G = - RTlnK_c

Given that T = 298 K

                 R = 8.315 J/mol·K

        \Delta G = -8.314 * 298 * ln (0.5)

               = -1717.32 J/mol

               = -1.7 \ kJ/mol

5 0
4 years ago
Read 2 more answers
To make some oatmeal, Sally combined 40 grams of oatmeal, 10 grams of maple syrup, and some warm water. If the combined mass was
Flura [38]
100-40-10= 50 grams of water
8 0
3 years ago
6 show that I 6x² – sxy-6900 &
Andrei [34K]

Answer:

6gkwkskekekkr

Explanation:

jakksksksjjdjdjdjdjdjdkskjj

7 0
3 years ago
PLEASE HELP!?!.!,! What are the products of the combustion of a hydrocarbon?
Tatiana [17]

Answer:

carbon dioxide and water

Explanation:

Example: Combustion of Methane (CH₄(g))

CH₄(g) + 2O₂(g) => CO₂(g) + 2H₂O(g)**

____________________

Note: The combustion of any hydrocarbon produces CO₂ & H₂O. That is,

Ethane (C₂H₆) + O₂ => CO₂(g) + H₂O(g)

Propane (C₃H₈) + O₂ => CO₂(g) + H₂O(g)

Butane (C₄H₁₀) + O₂ => CO₂(g) + H₂O(g)

The issue remaining is to balance the reaction equation. For these type equation balance Carbon 1st, then Hydrogen and finish with Oxygen. Balancing in this order leaves Oxygen which can be balanced using fractions. If problem requires lowest whole number ratios of elements, simply multiply entire equation by 2 to get standard equation*

______________________

*Standard Equation is defined as the smallest whole number ratios of elements. The 'standard equation' is significant in that it is assumed to be at STP conditions; i.e., 0⁰C (=273K) & 1.0 Atmosphere pressure.

  • Ethane (C₂H₆) + 7/2O₂(g) => 2CO₂(g) + 3H₂O(g)

    => 2C₂H₆ + 7O₂(g) => 4CO₂(g) + 6H₂O(g)  <= Standard Form of Rxn

  • Propane (C₃H₈) + 5O₂(g) => 3CO₂(g) + 4H₂O(g) <= Standard Form of Rxn (no need to balance with the '2' multiple)
  • Butane (C₄H₁₀) + 13/2O₂ => 4CO₂(g) + 5H₂O(g)

    => 2C₃H₈ + 13O₂(g) => 4CO₂(g) + 5H₂O(g) <= Standard Form of Rxn

______________________

**Also, note that water, H₂O(g), is listed as a gas. In some cases it will be listed as a liquid, H₂O(l).

3 0
4 years ago
Read 2 more answers
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