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topjm [15]
3 years ago
6

Give a power series representation for the function f(x) x^3/(1 + 9x^2)

Mathematics
1 answer:
Nata [24]3 years ago
6 0

Recall that for |x|, we have

\displaystyle\frac1{1-x}=\sum_{n\ge0}x^n

Replace x with -9x^2 and we get

\displaystyle\frac1{1-(-9x^2)}=\sum_{n\ge0}(-9x^2)^n=\sum_{n\ge0}(-9)^nx^{2n}

Lastly, multiply this by x^3, so that

\boxed{f(x)=\displaystyle\sum_{n\ge0}(-9)^nx^{2n+3}}

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Simplify -2.9f + .9f -12 - 4
Natalka [10]

\huge\text{Hey there!}

\large\text{-2.9f + 0.9f -12 - 4}\\\\\large\text{COMBINE the LIKE TERMS}\\\\\large\text{(-2.9f + 0.9f) + (-12 - 4)}\\\\\large\text{(-2.9f + 0.9f) = \bf{-2f}}\\\\\large\text{(-12 - 4) = \bf{-16}}\\\\\large\text{= \bf{-2f - 16}}\\\\\\\boxed{\boxed{\large\text{Answer: \bf{-2f - 16}}}}\huge\checkmark

\text{Good luck on your assignment and enjoy your day!}

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6 0
3 years ago
The product of three and a squared number is twice the sum of the number and four
Mamont248 [21]
From the text of the task we can write the equation:


3 x^{2} =2(x+4)\\
\\
3x^2=2x+8\\
\\
3x^2-2x-8=0\\
\\
\Delta=(-2)^2-4.3.(-8)=4+96=100\\
\\
x=\frac{2 \pm\sqrt{100}}{2.3}=\frac{2 \pm10}{6}\\
\\
x_1=\frac{2-10}{6}=-\frac{8}{6}=-\frac{4}{3}\\
\\
x_2=\frac{2+10}{2.3}=\frac{12}{6}=2
7 0
3 years ago
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[ Please help! ] Choose the equation that represents the graph below.
Kitty [74]

The line crosses the x -axis at point (9,0) and the y-axis at point (0,6).

If the equation of the line is y=kx+b, then substitute the coordinates of the points into this equation:

1) 0=9k+b;

2) 6=b.

Substitute the second equation into the first:

9k+6=0,\\ \\k=-\dfrac{2}{3}.

The equation of the line is

y=-\dfrac{2}{3}x+6.

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8 0
3 years ago
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levacccp [35]

Answer:

Step-by-step explanation:

7x - 8(2x - 3) + 2 = 8

Expand bracket and Minus 2 on both sides

7x - 16x + 24 = 6

Minus 24 on both sides, and simplify the "x's"

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Divide by -9 on both sides

x = 2

5 0
3 years ago
How do you find slope
Anit [1.1K]
This is how i can explain.....To find slop you need to count the number of units up and then right if your line is going down. 
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3 years ago
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