A rectangle has a base of 5 inches and a height of 7 inches. If the dimensions are cut in half, what will happen to the

Which terms in the following expression are like terms?

Alinara [238K]

9514 1404 393

Answer:

(c) 5x and 3x, and 4 and 1

Step-by-step explanation:

Like terms have the same variable(s) to the same power(s).

The terms of this expression are ...

x^3: variable x, power 3
5x: variable x, power 1
-3x: variable x, power 1
3y: variable y, power 1
4: no variable
-1: no variable

The like terms are {5x, -3x}, which have the x-variable to the first power, and {4, -1}, which have no variable.

6 0

2 years ago

A company that teaches self-improvement seminars is holding one of its seminars in Middletown. The company pays a flat fee of $1

Nutka1998 [239]

Answers:

To reach the breakeven point, how many attendees will that take? 117

What will be the company's total expenses and revenues? $1755 for each

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Explanation:

x = number of attendees

C(x) = cost function for the company

C(x) = 14x+117

This is because the company pays $14 per person, so x of them accounts for 14x dollars. Then we add on the flat fee of $117 to get 14x+117 dollars overall.

In contrast, the revenue is

R(x) = 15x

because each attendee brings in $15 for the company

The breakeven point is when the cost and revenue are the same. This produces a profit of $0.

R(x) = C(x)

15x = 14x+117

15x-14x = 117

x = 117

If 117 people attend the seminar, then the company breaks even.

To check this, we'll compute the cost and revenue

C(x) = 14x+117

C(117) = 14*117+117

C(117) = 1755

R(x) = 15x

R(117) = 15*117

R(117) = 1755

The cost and revenue is $1755 for each. Because we get the same value, this confirms the correct x value.

Since 117 people is the breakeven point, the company should aim for an attendee count above this, so they can get a positive profit. At some point, there is a max capacity so x can't go up forever.

7 0

1 year ago

PLS HELP ASAP WILL MARK BRAINLIEST Determine whether each relation is a function. Explain your reasoning.

Mariana [72]

No, it is not a function, since 6 is repeating itself and the x should never repeat if it’s a function.

3 0

2 years ago

Suppose I ask you to pick any four cards at random from a deck of 52, without replacement, and bet you one dollar that at least

Tatiana [17]

Answer:

a) No, because you have only 33.8% of chances of winning the bet.

b) No, because you have only 44.7% of chances of winning the bet.

Step-by-step explanation:

a) Of the total amount of cards (n=52 cards) there are 12 face cards (3 face cards: Jack, Queen, or King for everyone of the 4 suits: clubs, diamonds, hearts and spades).

The probabiility of losing this bet is the sum of:

- The probability of having a face card in the first turn

- The probability of having a face card in the second turn, having a non-face card in the first turn.

- The probability of having a face card in the third turn, having a non-face card in the previous turns.

- The probability of having a face card in the fourth turn, having a non-face card in the previous turns.

1) The probability of having a face card in the first turn

In this case, the chances are 12 in 52:

$P_1=P(face\, card)=12/52=0.231$

2) The probability of having a face card in the second turn, having a non-face card in the first turn.

In this case, first we have to get a non-face card (there are 40 in the dech of 52), and then, with the rest of the cards (there are 51 left now), getting a face card:

$P_2=P(non\,face\,card)*P(face\,card)=(40/52)*(12/51)=0.769*0.235=0.181$

3) The probability of having a face card in the third turn, having a non-face card in the first and second turn.

In this case, first we have to get two consecutive non-face card, and then, with the rest of the cards, getting a face card:

$P_3=(40/52)*(39/51)*(12/50)\\\\P_3=0.769*0.765*0.240=0.141$

4) The probability of having a face card in the fourth turn, having a non-face card in the previous turns.

In this case, first we have to get three consecutive non-face card, and then, with the rest of the cards, getting a face card:

$P_4=(40/52)*(39/51)*(38/50)*(12/49)\\\\P_4=0.769*0.765*0.76*0.245=0.109$

With these four probabilities we can calculate the probability of losing this bet:

$P=P_1+P_2+P_3+P_4=0.231+0.181+0.141+0.109=0.662$

The probability of losing is 66.2%, which is the same as saying you have (1-0.662)=0.338 or 33.8% of winning chances. Losing is more probable than winning, so you should not take the bet.

b) If the bet involves 3 cards, the only difference with a) is that there is no probability of getting the face card in the fourth turn.

We can calculate the probability of losing as the sum of the first probabilities already calculated:

$P=P_1+P_2+P_3=0.231+0.181+0.141=0.553$

There is 55.3% of losing (or 44.7% of winning), so it is still not convenient to bet.

5 0

3 years ago

The taxi costs $2.25 for the first mile plus 15cents for each additional tenth of a mile. For a 5.2 mile trip, Eric payed $10 an

Verizon [17]

2.25 for the first mile. That leaves 4.2 miles.

4 * 0.1 = 0.4

0.15 * 4 = $6.00

0.15 * 2 = 0.3

$6.30 + $2.25 = $8.55

$10.00 - $8.55 = $1.45

The driver's tip was $1.45.

7 0

2 years ago