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photoshop1234 [79]
3 years ago
11

Hans is a film director, and he is attempting to shoot a complicated scene for a movie set in the American West. In the scene, a

bank robber tries to make a daring escape atop a moving train. Alongside the train, the movie's hero, a lawman, rides on horseback.  Hans plans the scene so that the train will move at a constant speed. The lawman on horseback, while moving in the same direction as the train, will cover the same amount of distance in the same amount of time as the train. The bank robber will move along the train's roof at a speed of 4 meters per second. He will also move in the same direction as the train so that their speeds will combine.  Hans wants to organize the scene so that a camera at rest on the ground will shoot the train as it moves past. He wants the robber, from the camera's point of reference, to be moving at a rate of 25 meters per second. For this scene to work as Hans has imagined it, how fast must the lawman's horse be able to run?
Mathematics
2 answers:
emmasim [6.3K]3 years ago
4 0
The answer would be 45 meters per second.
svetlana [45]3 years ago
4 0

Answer:

It's actually 21 meters per second. I just took it

Step-by-step explanation:

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Which number is a prime number 2 or 4or<br> 14 or 24
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A stainless steel patio heater is a square pyramid. The length of one side of the base is 22.4 in. The slant height of the pyram
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Answer:

93.03 in

Step-by-step explanation:

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A diver takes a running leap off of a 40 foot cliff into a pool of water. When she is 5 feet from the cliff,
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2 years ago
This figure is made up of a quadrilateral and a semicircle.
Arturiano [62]

Answer:

The correct option is B. The area of the figure is 40.4 units².

Step-by-step explanation:

The line AB divides the figure in two parts one is a rectangle and another is semicircle.

The distance formula is

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

The length of AB is

AB=\sqrt{(2+3)^2+(4-2)^2}=\sqrt{25+4}=\sqrt{29}

The length of AD is

AD=\sqrt{(-1+3)^2+(-3-2)^2}=\sqrt{4+25}=\sqrt{29}

Since AB=AD, therefore ABCD is a square. The area of the of square is

A_1=a\times a=\sqrt{29}\times \sqrt{29} =29

The area of square is 29 units².

The area of a semicircle is

A_2=\frac{\pi}{2}r^2

Since AB is the diameter of the semicircle, therefore the radius of the semicircle is

r=\frac{d}{2}=\frac{\sqrt{29}}{2}

The area of the semicircle is

A_2=\frac{3.14}{2}(\frac{\sqrt{29}}{2})^2=40.3825

The area of the figure is

A=A_1+A_2=29+11.2825=40.3825\approx 40.4

Therefore the area of the figure is 40.4 units². Option B is correct.

5 0
3 years ago
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