First we need to find slope of given line −4x+3y=−2
So convert it into slope intercept form y=mx+b
−4x+3y=−2
3y=4x−2
y=4/3x−2/3
Comparing above equation with y=mx+b gives m=4/3
Hence slope of given line is 4/3.
<em>We need slope of perpendicular line which is always "negative reciprocal of given slope"</em>.
Negative of 4/3 is -4/3.
taking reciprocal gives -3/4
Hence slope of required perpendicular line is m=-3/4
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Now we need to find y-intercept of −7x−7y=6
y-intercept is always the y-value when x=0 so let's plug x=0 into −7x−7y=6
−7(0)−7y=6
0−7y=6
−7y=6
y=-6/7
y-intercept is also called "b" in y=mx+b
hence b=-6/7
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Now we know that slope of perpendicular line is m=-3/4 and y-intercept b=-6/7
so plug both into formula y=mx+b
We get Final answer is ![y=-\frac{3}{4}x-\frac{6}{7}](https://tex.z-dn.net/?f=%20y%3D-%5Cfrac%7B3%7D%7B4%7Dx-%5Cfrac%7B6%7D%7B7%7D%20)
Answer should be A. 2x + y = 4, hopefully this helped :]
Answer:
(0, -9)
Step-by-step explanation:
On a coordinate plane, a curved line with a minimum value of (0, negative 9) and maximum values of (negative 2.3, 16) and (2.3, 16), crosses the x-axis at (negative 3, 0), (negative 1, 0), (1, 0), and (3, 0), and crosses the y-axis at (0, negative 9). Which is a y-intercept of the graphed function? (–9, 0) (–3, 0) (0, –9) (0, –3)
The y-intercept is the point where x = 0, and It says there that the graph crosses the y-axis at (0, -9)