3a+b+c
The perimeter is two times one side (to account for the opposite) and two times the adjacent side. So if the sides would be x and y, the perimeter would be 2*x + 2*y.
So, knowing that the sum is 16a+8b-6c, if we subtract the given side 5a+3b-4c from this, what remains is two times the "other" side:
16a+8b-6c - 2*(5a+3b-4c) =
16a+8b-6c -10a-6b+8c =
6a+2b+2c
half of that is
(6a+2b+2c)/2 = 3a+b+c
Answer:
∠DAB = ∠DBA
Then AD=DB from above statement
Step-by-step explanation:
kindly see attached picture
hope it helped you:)
Answer:
-4y - 7x^3 + 2
Step-by-step explanation:
So first lets combine the y terms together, doing this we get:
-4y + 1 - x^3 - 3x^3 + 1 - 3x^3
Now lets combine the terms with x^3 together
-4y + 1 - 7x^3 + 1
Lastly, lets add the constants
-4y - 7x^3 + 2