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2 years ago

Ned help with this don't anwser if you don't know

Mathematics

1 answer:

Delvig [45]2 years ago

6 0

Answer:

f(x) = 2x + 2

Step-by-step explanation:

1×2=2+2=4

3×2=6+2=8

and keep going

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Consider the following statement. If r is any rational number and s is any irrational number, then r s is irrational. (a) Which

olganol [36]

Answer:

(a) If r is any rational number and s is any irrational number, then r/s is rational

(b) The statement is false when r is 0

Step-by-step explanation:

Given

$r \to$ rational number

$s \to$ irrational number

$\frac{r}{s} \to$ irrational number

Solving (a): The negation

To get the negation of a statement, we only need to negate the end result

In other words, the number type of r and s will remain the same, but r/s will be negated.

So, the negation is:

$r \to$ rational number

$s \to$ irrational number

$\frac{r}{s} \to$ rational number

Solving (b): When r/s is irrational is false

Given that:

$\frac{r}{s} \to$ irrational number

Set r to 0

So:

$\frac{r}{s} = \frac{0}{s}$

$\frac{r}{s} = 0$ -- rational

<em>Hence, the statement is false when r is 0</em>

8 0

2 years ago

A $79 television is on sale for $65. What percent discount was given? <br>

pickupchik [31]

Answer:

The discount percentage has been given: ($ 65 / $ 79) x 100 = 82.27%

So the discount percentage is: 100% -82.27% = 17.72%

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Asked what the central limit theorem says, a student replies, As you take larger and larger samples from a population, the histo

Arada [10]

Answer:

A. No, the student is not right. The central limit theorem says nothing about the histogram of the sample values. It deals only with the distribution of the sample means.

Step-by-step explanation:

No, the student is not right. The central limit theorem says nothing about the histogram of the sample values. It deals only with the distribution of the sample means. The central limit theorem says that if we take a large sample (i.e., a sample of size n > 30) of any distribution with finite mean $\mu$ and standard deviation $\sigma$ , then, the sample average is approximately normally distributed with mean $\mu$ and variance $\sigma^2/n$ .