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2 years ago

A company makes muesli which contains nuts and sultanas.

Mathematics

2 answers:

Alik [6]2 years ago

8 0

Answer: ok, so,

Step-by-step explanation:

all you do is

8 x 9

11 x 12

14 x 17

15 x 9

then add all the numbers together to make the total

610divided by 50 = answer

blsea [12.9K]2 years ago

6 0

A company makes muesli which contains nuts and sultanas.

They counted the number of nuts in 50 individual serving packets.

They drew a table.

Number Midpoint Number of

of nuts (x) packets (f) f.x

4 - 6 5 3 15

7-9 8 9

10 - 12 11 12

13 - 15 14 17

16 - 18 17 9

To Find :

complete the table

calculate and estimate for the mean

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Write an equation to model growth or decay in the following scenario. A stock is declining at a rate of 25% of its value every 2

yawa3891 [41]

The exponential function that models this situation is:

$y(t) = 225(0.75)^{\frac{t}{2}}$

------------------------------------------

A decaying exponential function has the following format:

$y(t) = y(0)(1 - r)^t$

In which:

y(0) is the initial value.
r is the decay rate, as a decimal.

In this problem:

The stock started at $225, thus $y(0) = 225$ .
Declines at a rate of 25% every 2 weeks, thus $r = 0.25, t = \frac{t}{2}$

The equation is:

$y(t) = y(0)(1 - r)^t$

$y(t) = 225(1 - 0.25)^{\frac{t}{2}}$

$y(t) = 225(0.75)^{\frac{t}{2}}$

A similar problem is given at brainly.com/question/24282972

3 0

2 years ago

Hello again! This is another Calculus question to be explained.

podryga [215]

Answer:

See explanation.

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Functions

Function Notation

Exponential Property [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$
Exponential Property [Root Rewrite]: $\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}$

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Derivative Property [Addition/Subtraction]: $\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

We are given the following and are trying to find the second derivative at x = 2:

$\displaystyle f(2) = 2$

$\displaystyle \frac{dy}{dx} = 6\sqrt{x^2 + 3y^2}$

We can differentiate the 1st derivative to obtain the 2nd derivative. Let's start by rewriting the 1st derivative:

$\displaystyle \frac{dy}{dx} = 6(x^2 + 3y^2)^\big{\frac{1}{2}}$

When we differentiate this, we must follow the Chain Rule: $\displaystyle \frac{d^2y}{dx^2} = \frac{d}{dx} \Big[ 6(x^2 + 3y^2)^\big{\frac{1}{2}} \Big] \cdot \frac{d}{dx} \Big[ (x^2 + 3y^2) \Big]$