To rearrange you must first simplify
aq-ac=d
add ac to each side:
aq=d+ac
then divide by a:
q=(d/a)+c and this is your answer
Answer: $50.91
Step-by-step explanation:
The following information can be gotten from the question;
Cost of sweater = $49.95,
Cost of slacks = $68.59 each,
Cost of 2 slacks = $68.59 × 2
= $137.18
Cost of suit = $429.99.
Total cost = $49.95 + $137.18 + $429.99 = $617.12
Sales tax = 8.25%
The sales tax that Mike owe will be:
= 8.25% × $617.12
= 0.0825 × $617.12
= $50.91
Mike will have to pay a sales tax of $50.91
Answer:
Amira used 4 balloons for each balloon animal.
Step-by-step explanation:
From the table, we can conclude that:
For 20 animals being sold by her, the leftover balloons were 180.
Then there is an increase in the number of animals being sold. She now sells 29 animals. So, the increase in animals being sold is given as:
29 - 20 = 9.
So, 9 more animals were sold. The balloons used for these 9 animals can be obtained by taking the difference of the leftover balloons for the two days.
The difference of the leftover balloons = 180 - 144 = 36.
So, 36 balloons were used for selling 9 more animals.
Similarly, there is an increase of another 9 animals when 38 animals were sold as 38 - 29 = 9. Also, the balloons used in this case is 36 only as the difference of the leftover balloons is 36.
144 - 108 = 36
Therefore, we conclude that for selling 9 balloon animals, Amira used 36 balloons.
Number of balloons used for 9 balloon animals = 36
∴ Number of balloons used for 1 balloon animal =
(Unitary method)
Thus, Amira used 4 balloons for each balloon animal.
Answer:
Answer is 4 3/5
Step-by-step explanation:
Rewriting our equation with parts separated
=1+15+3+25
Solving the whole number parts
1+3=4
Solving the fraction parts
15+25=35
Combining the whole and fraction parts
4+35=435
So,
Matt answered 20 out of 25 questions.

We need to get the denominator to be 100. We can do that by multiplying the fraction by a form of 1.

From here, it should be easy to see that Matt has answered 80% of his test.