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2 years ago

What is the answer for my khan academy homework

Mathematics

2 answers:

Verdich [7]2 years ago

7 0

Answer:

Step-by-step explanation:

16 divided by 4 is 4

8 + 4 : 12

Svetllana [295]2 years ago

6 0

Answer:12

Step-by-step explanation: plug the 16 into were the a is in the question

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Alguien me ayuda porfiss

zimovet [89]

Answer:

Step-by-step explanation: a, c, and e

4 0

2 years ago

pls There are (4^9)^5 ⋅ 4^0 books at the library. What is the total number of books at the library? A.4^9 B. 4^45 C. 4^46 D. 1

jekas [21]

We know that there are (4^9)^5 ⋅ 4^0 at the library, so we just need to simplify this to get the answer.
(4^9)^5 ⋅ 4^0
=(4^9)^5×1
=(4^9)^5
=4^9×5
=4^45. As a result, the total number of books at the library is 4^45 books at the library or B is the final answer. Hope it help!

6 0

3 years ago

Step by step explanation on how to solve -22-(6)(-9)/3

timofeeve [1]

Answer:

-4

Step-by-step explanation:

-22-(6)(-9)/3

my bad it shows explanation

5 0

3 years ago

Read 2 more answers

Average movie prices in the United States are, in general, lower than in other countries. It would cost $78.73 to buy three t

likoan [24]

Average movie ticket cost in Japan = $17.23

Average movie ticket cost in Switzerland = $ 13.52

Step-by-step explanation:

Let x be the cost of movie ticket in Japan and y be the cost of movie ticket in Switzerland.

Given 3 ticket in Japan + 2 tickets in Switzerland = $78.73

⇒ 3x + 2y = 78.73 – – – – (1)

Given 3 ticket in Switzerland + 2 tickets in Japan = $75.02

⇒ 3y + 2x = 75.02

⇒ 2x + 3y = 75.02– – – – – (2)

Now, to solve (1) and (2), we multiply equation (1) by 2 and equation (2) by 3.

(1) × 2 ⇒ 6x + 4y = 157.46 – – – – (3)

(2) × 3 ⇒ 6x + 9y = 225.06 – – – – (4)

Subtract (3) from (4), we get

6x + 9y – (6x + 4y)= 225.06 – 157.46

⇒ 6x + 9y – 6x – 4y= 67.6

⇒ 5y = 67.6

⇒ y = 13.52

Now substitute y = 13.52 in equation (1), we get,

(1) ⇒ 3x + 2(13.52) = 78.73

⇒ 3x = 78.73 – 27.04

⇒ x = 27.23

Hence, Average movie ticket cost in Japan is $27.23

Average movie ticket cost in Switzerland is $ 13.52.

4 0

3 years ago

Find the general solution to 1/x dy/dx - 2y/x^2 = x cos x, y(pi) = pi^2

Finger [1]

Answer:

$\frac{y}{x^2}=\sin x+\pi$

Step-by-step explanation:

Consider linear differential equation $\frac{\mathrm{d} y}{\mathrm{d} x}+yp(x)=q(x)$

It's solution is of form $y\,I.F=\int I.F\,q(x)\,dx$ where I.F is integrating factor given by $I.F=e^{\int p(x)\,dx}$ .

Given: $\frac{1}{x}\frac{\mathrm{d} y}{\mathrm{d} x}-\frac{2y}{x^2}=x\cos x$

We can write this equation as $\frac{\mathrm{d} y}{\mathrm{d} x}-\frac{2y}{x}=x^2\cos x$

On comparing this equation with $\frac{\mathrm{d} y}{\mathrm{d} x}+yp(x)=q(x)$ , we get $p(x)=\frac{-2}{x}\,\,,\,\,q(x)=x^2\cos x$

I.F = $e^{\int p(x)\,dx}=e^{\int \frac{-2}{x}\,dx}=e^{-2\ln x}=e^{\ln x^{-2}}=\frac{1}{x^2}$ { formula used: $\ln a^b=b\ln a$ }

we get solution as follows:

$\frac{y}{x^2}=\int \frac{1}{x^2}x^2\cos x\,dx\\\frac{y}{x^2}=\int \cos x\,dx\\\\\frac{y}{x^2}=\sin x+C$

{ formula used: $\int \cos x\,dx=\sin x$ }

Applying condition: $y(\pi)=\pi^2$

$\frac{y}{x^2}=\sin x+C\\\frac{\pi^2}{\pi}=\sin\pi+C\\\pi=C$

So, we get solution as :

$\frac{y}{x^2}=\sin x+\pi$

4 0

3 years ago