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3 years ago

5

The function "g" is defined as g(x)=5x+a, where "a" is a constant. If g(4)=31, what is the value of "a"?

1 answer:

babymother [125]3 years ago

6 0

The a is 11

g(4)=20+a
g(4)=31
31-20=11
a=11

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The resting heart rate for an adult horse should average about μ = 43 beats per minute. Let x be a random variable that represen

lara31 [8.8K]

Answer:

451.5

Step-by-step explanation:

I'm rusted on the mathematics

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2 years ago

Please solve 5 f <br> (Trigonometric Equations)<br> #salute u if u solved it

Zanzabum

Answer:

$\beta=45\degree\:\:or\:\:\beta=135\degree$

Step-by-step explanation:

We want to solve $\tan \beta \sec \beta=\sqrt{2}$ , where $0\le \beta \le360\degree$ .

We rewrite in terms of sine and cosine.

$\frac{\sin \beta}{\cos \beta} \cdot \frac{1}{\cos \beta} =\sqrt{2}$

$\frac{\sin \beta}{\cos^2\beta}=\sqrt{2}$

Use the Pythagorean identity: $\cos^2\beta=1-\sin^2\beta$ .

$\frac{\sin \beta}{1-\sin^2\beta}=\sqrt{2}$

$\implies \sin \beta=\sqrt{2}(1-\sin^2\beta)$

$\implies \sin \beta=\sqrt{2}-\sqrt{2}\sin^2\beta$

$\implies \sqrt{2}\sin^2\beta+\sin \beta- \sqrt{2}=0$

This is a quadratic equation in $\sin \beta$ .

By the quadratic formula, we have:

$\sin \beta=\frac{-1\pm \sqrt{1^2-4(\sqrt{2})(-\sqrt{2} ) } }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm \sqrt{1^2+4(2) } }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm \sqrt{9} }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm3}{2\cdot \sqrt{2} }$

$\sin \beta=\frac{2}{2\cdot \sqrt{2} }$ or $\sin \beta=\frac{-4}{2\cdot \sqrt{2} }$

$\sin \beta=\frac{1}{\sqrt{2} }$ or $\sin \beta=-\frac{2}{\sqrt{2} }$

$\sin \beta=\frac{\sqrt{2}}{2}$ or $\sin \beta=-\sqrt{2}$

When $\sin \beta=\frac{\sqrt{2}}{2}$ , $\beta=\sin ^{-1}(\frac{\sqrt{2} }{2} )$

$\implies \beta=45\degree\:\:or\:\:\beta=135\degree$ on the interval $0\le \beta \le360\degree$ .

When $\sin \beta=-\sqrt{2}$ , $\beta$ is not defined because $-1\le \sin \beta \le1$

4 0

3 years ago

Pleaseee someone help me in this question ihave bben eating for half an hour and no one helped me.

pav-90 [236]

Cross Multiply by 'x - 5'
Hence
y(x - 5) = 4 -3x
xy - 5y = 4 - 3x

Move all the terms containing an 'x' to one side of the equals and all the others to the opposite side.
xy + 3x = 4 + 5y
Factor out 'x'
x(y + 3) = 4 + 5y
'Cross' divide by 'y + 3'
x = ( 4 + 5y) / (y + 3 )

'x' is now the subject.

8 0

3 years ago

Please help due ASAP <br> Show workings please

Nostrana [21]

Step-by-step explanation:

I don't know if this is the right way to so it, but I would do it like this

since a triangle has 180 degrees, the angles all have to add up to 180

So 180 = a + b + c

we already know a, its 95

So 180 = 95 + b + c

now we know the equation for b, so we'll just put it there instead of the b, and since the angles are the same, we should put it instead of c too

180 = 95 + (4x-15) + (4x-15)

now subtract 95 from both sides

85 = (4x-15) + (4x-15)

add the xs and numbers together

85 = 8x - 30

now add the 30 to both sides

115 = 8x

divide by 8

your x is 14 3/8 or 14.375 or 115/8

that's not your angle, that's your x

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2 years ago

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Vadim26 [7]

I think I’d B help this helps

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2 years ago