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Len [333]
2 years ago
11

The price of a 9 minute phone call is ​$3.15. What is the price of a 13 minute phone​ call?

Mathematics
1 answer:
tino4ka555 [31]2 years ago
4 0

Answer:

5.95

Step-by-step explanation:

9 min-> $3.15

1 min -> 0.35

17 min->5.95

plese give me brainliest

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What is this called, like whats the name of this thing??<br> {18 ≤ y ≤ 30}
Tpy6a [65]

Answer:

An inequality.

Step-by-step explanation:

This gives the range of values that y can take.

It can equal 18 or be greater than eighteen but it also could be 30 or less than thirty.

WE read the signs starting from y to the left  and to the right.

So y is greater or equal to 18 and less than or equal to 30.

3 0
3 years ago
What is another way to show 1/8 + 5/8
12345 [234]
1          5
-    +     -
8           8

or

1/8 +  1.25/2

8 0
3 years ago
Read 2 more answers
A confidence interval (CI) is desired for the true average stray-load loss u (watts) for a certain type of induction motor when
Genrish500 [490]

Answer:

A) CI = (57.12 , 59.48)

B) CI = (57.71 , 58.89)

C) CI = (57.53 , 59.07)

D) n = 239.63

Step-by-step explanation:

a)

given data:

mean, \bar X = 58.3

standard deviation, σ = 3

sample size, n = 25Given CI level is 95%, hence α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025,

Zc = Z(α/2) = 1.96

ME = Zc * σ \sqrt{n}

ME = 1.96 * 3 \sqrt{25}

ME = 1.18

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 1.96 * 3\sqrt{25} , 58.3 + 1.96 * 3\sqrt{25})

CI = (57.12 , 59.48)

b)

Given data:

mean, \bar X = 58.3

standard deviation, σ = 3

sample size, n = 100

Given CI level is 95%, hence α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025, Zc = Z(α/2) = 1.96

ME = zc * σ \sqrt{n}

ME = 1.96 * 3\sqrt{100}

ME = 0.59

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 1.96 * 3\sqrt{100} , 58.3 + 1.96 * 3\sqrt{100})

CI = (57.71 , 58.89)

c)

sample mean, \bar X = 58.3

sample standard deviation, σ = 3

sample size, n = 100

Given CI level is 99%, hence α = 1 - 0.99 = 0.01

α/2 = 0.01/2 = 0.005, Zc = Z(α/2) = 2.58

ME = Zc * σ \sqrt{n}

ME = 2.58 * 3\sqrt{100}

ME = 0.77

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 2.58 * 3\sqrt{100} , 58.3 + 2.58 * 3/\sqrt{100}

CI = (57.53 , 59.07)

D)

Given data:

Significance Level, α = 0.01,

Margin or Error, E = 0.5,

σ = 3

The critical value for α = 0.01 is 2.58.

for calculating population mean we used

n \geq (zc *σ/E)^2

n = (2.58 * 3/0.5)^2

n = 239.63

7 0
3 years ago
Does anyone know the answer to this problem?
Mariana [72]

The regression equation is y = 16.585x - 639.769 and the linear correlation coefficient indicates a strong linear relationship

<h3>How to determine the regression equation?</h3>

To do this, we make use of a statistical calculator;

Using the statistical calculator, we have the following summary:

  • Sum of X = 554
  • Sum of Y = 4070
  • Mean X = 69.25
  • Mean Y = 508.75
  • Sum of squares (SSX) = 725.5
  • Sum of products (SP) = 12032.5
  • Correlation coefficient, r = 0.9768

The regression equation is

ŷ = bx + a

Where:

b = SP/SSX = 12032.5/725.5 = 16.58511

a = MY - bMX = 508.75 - (16.59*69.25) = -639.76912

Hence, the regression equation is y = 16.585x - 639.769

<h3>The number of cans sold at 90 degrees F</h3>

This means that"

x = 90

So, we have:

y = 16.585 * 90 - 639.769

Evaluate

y = 852.881

Approximate

y = 853

Hence, 853 cans were sold at 90 degrees F

<h3>The linear correlation coefficient</h3>

In (a), we have:

r = 0.9768

This means that the linear correlation coefficient is 0.9768

<h3>The conclusion</h3>

We have:

r = 0.9768

The above value is closer to 1 because

|r| > 0.9

i.e.

0.9768 > 0.9

Hence, the linear correlation coefficient indicates a strong linear relationship

Read more about regression at:

brainly.com/question/17844286

#SPJ1

6 0
2 years ago
Tell me the coordinates to graph it plz
Katarina [22]

Answer:

x=2, y=3

Step-by-step explanation:

7 0
3 years ago
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