let the numbers be x and y
x + y = 1600 ----*
12%x = 20%y
0.12x = 0.2y
y = <u>0</u><u>.</u><u>1</u><u>2</u><u>x</u>
0.2
y = 0.6x
substitute in * eqn
x + 0.6x = 1600
1.6x = 1600
x = 1000
then,
y = 0.6*1000
y = 600
the numbers are 1000 and 600
Answer: please tell me if you got the answer to this problem. I’ve been looking for the past 2days. :)
Step-by-step explanation:
Answer:
zero
Step-by-step explanation:
Answer:
77
Step-by-step explanation:
The information is really hard to follow, you should ask the question with a screenshot of the data table.
