Put the numbers in order.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.
Step 2: Find the median.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.
Step 3: Place parentheses around the numbers above and below the median.
Not necessary statistically, but it makes Q1 and Q3 easier to spot.
(1, 2, 5, 6, 7), 9, (12, 15, 18, 19, 27).
Step 4: Find Q1 and Q3
Think of Q1 as a median in the lower half of the data and think of Q3 as a median for the upper half of data.
(1, 2, 5, 6, 7), 9, ( 12, 15, 18, 19, 27). Q1 = 5 and Q3 = 18.
Step 5: Subtract Q1 from Q3 to find the interquartile range.
18 – 5 = 13.
Answer:
343,000
Step-by-step explanation:
Imagine there are a bunch of zeros to the right of the thousandths decimal place. If the 10 is raised to the fifth power, you want to move the decimal place to the right 5 times. This makes the new number 343,000. Since there are only 3 sig figs in the original number, there would be no decimal place in the standard form.
3^9
3x3x3x3x3x3x3x3x3
9x3
27x3
81x3
243x3
729x3
2187x3
6561x3
3 to the 9th power is 19683
30 books = 6 months
In 1 month 30/6= 5
He read 5 books in one month
So, he read 45 books
45/5= 9
<em>He read 45 books/9 months</em>
The first if a twisted version of a Fibonacci sequence :P
If a1=1.2 and a2=2.3 and a(n)=a(n-1)+a(n-2)
a3=3.5, a4=5.8, a5=9.3
So the first five terms are: 1.2, 2.3, 3.5, 5.8, 9.3
The second is another modified Fibonacci sequence...
If a3=-5 and a4=3 then:
3=-5+a2, a2=8
-5=8+a1, a1=-13
a5=-5+3=-2
a6=-2+3=1
So the first six terms are -13, 8, -5, 3, -2, 1
