f(x).g(x) = (x^2+6x)(2x^3) = 2x^5+12x^4
f(0).g(2) =(0^2+6*0)(2*2^3) =0*16=0
f(1).g(1)=(1^2+6*1)(2*1^3)=(1+6)(2*1)=7*2=14
g(x).g(x)=(2x^3)(2x^3)=2*2*x^3*x^3=4x^6
Answer:
1.20 ÷ 4 = 0.30 per unit
Please mark as brainliest;)
Answer:
0.3333 = 33.33% probability that the employee will arrive between 8:15 a.m. and 8:25 a.m.
Step-by-step explanation:
A distribution is called uniform if each outcome has the same probability of happening.
The uniform distributon has two bounds, a and b, and the probability of finding a value between c and d is given by:

A particular employee arrives at work sometime between 8:00 a.m. and 8:30 a.m.
We can consider 8 am = 0, and 8:30 am = 30, so 
Find the probability that the employee will arrive between 8:15 a.m. and 8:25 a.m.
Between 15 and 25, so:

0.3333 = 33.33% probability that the employee will arrive between 8:15 a.m. and 8:25 a.m.
Answer:
B. 3
Step-by-step explanation:
we know 2x3 = 6 soo just add 2 zeros = 600