Answer:
15
Step-by-step explanation:
Answer:
15.866%
Step-by-step explanation:
We solve using z score formula
z = (x-μ)/σ, where
x is the raw score = 3,282 gallons of kerosene
μ is the population mean = 3,087 gallons of kerosene
σ is the population standard deviation = 195 gallons
For x > 3282 gallons
z = 3282 - 3087/195
z = 1
Probability value from Z-Table:
P(x<3282) = 0.84134
P(x>3282) = 1 - P(x<3282) = 0.15866
Converting to percentage
0.15866 × 100 = 15.866%
The percent of flights on these particular routes that will burn more than 3,282 gallons of kerosene is 15.866%
Answer: 127,500
Step-by-step explanation: I just used a calculator
Answer:
x = -3/2
Step-by-step explanation:
Lets first multiply the entire equation by 4 to get rid of the fractions.
1+2+4x = -3
3+4x = -3
4x = -6
x = -6/4
x = -3/2
