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Alchen [17]
3 years ago
9

On a flight from New York to London, an airplane travels at a constant speed. An equation relating the distance traveled in mile

s, d, to the number of hours flying, t, is . How long will it take the airplane to travel 800 miles? Do not include units (hours) in your answer.
Mathematics
1 answer:
Anettt [7]3 years ago
6 0

Answer:

Step-by-step explanation:

The question is incomplete. Here is the complete question

On a flight New York to London an airplane travels at a constant speed. An equation relating the distance traveled in miles d to the number of hours flying t is t= 1/500d. How long will it take the airplane to travel 800 miles?

Speed is the change in distance if a body with respect to time. It is expressed mathematically according to the question as t = 1/500 × d

To determine the time it will take to travel 800miles, we will substitute d = 800 into the modeled equation.

t = 1/500 × 800

t = 800/500

t = 8/5

t = 1.6

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In politics, marketing, etc. we often want to estimate a percentage or proportion p. One calculation in statistical polling is t
aksik [14]

The absolute value inequality is given as |(p - 0.43)I ≤ 0.019

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<h3>How to describe the proportion using the absolute value inequality</h3>

The proportion p = 43% = 0.43

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The value of the proportion can then be said to lie between

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3 0
2 years ago
6. Steve is packing sacks for treats at a party. Every sack is exactly the same. Steve has 42 candy bars and 126 lollipops. a. W
Sergeu [11.5K]

Answer:

Greatest sack = 42

1 candy bar and 3 lollipops

<em></em>

Step-by-step explanation:

Represent Candy bars with C and Lollipops with L

C = 42

L= 126

Solving (a): Greatest number of treat sacks

To solve this, we simply calculate the GCF of C and L

42 = 2^1 * 3^1 * 7^1

126 = 2^1 * 3^2 * 7^1

Hence, the GCF is

GCF = 2^1 * 3^1 * 7^1

GCF = 42

Hence, greatest number of sack is 42

Solving (b): Number of treat in each sack.

To do this, we simply divide the number of C and L by the calculated GCF

For C:

Treats = \frac{C}{GCF}

Treats = \frac{42}{42}

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For L:

Treats = \frac{L}{GCF}

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3 years ago
How much would $500 invested at 3% interest compounded continuously be
77julia77 [94]

Answer:

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Step-by-step explanation:

598.60

You are given the equation 

A(t) = P*e^(rt) 

Where P = Principal 

r = interest rate 

t = time 

e is a mathematical constant equivalent to approx 2.71828 

You're told the initial Principal is $500, the interest rate is 3%, over 6 years. So you have everything that you need to solve the problem, just plug in the values and solve for A(6) 

A(t) = P*e^(rt) 

A(6) = 500 * e^(0.03 * 6) 

A(6) = 500 * e^(0.18) 

A(6) = 500 * 2.71828^(0.18) 

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A(6) = 598.60861 

So $500 invested 6 years ago at 3% would be worth $598.61 today.

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3 years ago
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