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1 year ago

10

Carnegie Learning, Inc.

1 answer:

Mnenie [13.5K]1 year ago

8 0

Answer:

B

Step-by-step explanation:

The y coordinate tells us when we are going up for down. So the rule would be (x, y + 5) So, the x coordinate stays the same and the y goes up 5.

(1,2) The 2 is the y coordinate. It will increase by 5 and become (1,7)

(3,2) The 2 is the y coordinate. It will increase by 5 and become (3,7)

(3,4) The 4 is the y coordinate. It will increase by 5 and become (3,9)

(1,4) The 4 is the y coordinate. It will increase by 5 and become (1,9)

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Algebraic expression for 8+6q+q

irina1246 [14]

All you can do to this expression is simplify.

You need to combine all "like terms." There are two q terms so you need to combine those. To combine "like terms", simply add their coefficients. 6q has a coefficient of 6 and q has a coefficient of 1. So:

$6q + 1q = 7q$

Therefore your end result is:

$8 +7q$

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3 years ago

Finding angle measure using triangles

Rainbow [258]

x = 58°

<u>Explanation:</u>

According to the diagram, lines HI and JK are parallel to each other.

∠AHI = 60°

∠JKI = 62°

∠JKI and ∠HIA are equal because when two lines are parallel then the corresponding angles are equal.

So,

∠JKI = ∠HIA = 62°

In ΔHIA,

∠AHI + ∠HIA + ∠IAH = 180°

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x = 180° - 122°

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3 years ago

-2-3x=3+1x what is the answer

Fofino [41]

-2-3x=3+1x
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-5=4x
x=-1.25

4 0

2 years ago

Read 2 more answers

Pls solve the simultaneous equation in the attachment.

siniylev [52]

Answer:

Part a) The solution is the ordered pair (6,10)

Part b) The solutions are the ordered pairs (7,3) and (15,1.4)

Step-by-step explanation:

Part a) we have

$\frac{x}{2}-\frac{y}{5}=1$ ----> equation A

$y-\frac{x}{3}=8$ ----> equation B

Multiply equation A by 10 both sides to remove the fractions

$5x-2y=10$ ----> equation C

isolate the variable y in equation B

$y=\frac{x}{3}+8$ ----> equation D

we have the system of equations

$5x-2y=10$ ----> equation C

$y=\frac{x}{3}+8$ ----> equation D

Solve the system by substitution

substitute equation D in equation C

$5x-2(\frac{x}{3}+8)=10$

solve for x

$5x-\frac{2x}{3}-16=10$

Multiply by 3 both sides

$15x-2x-48=30$

$15x-2x=48+30$

Combine like terms

$13x=78$

$x=6$

<em>Find the value of y</em>

$y=\frac{x}{3}+8$

$y=\frac{6}{3}+8$

$y=10$

The solution is the ordered pair (6,10)

Part b) we have

$xy=21$ ---> equation A

$x+5y=22$ ----> equation B

isolate the variable x in the equation B

$x=22-5y$ ----> equation C

substitute equation C in equation A

$(22-5y)y=21$

solve for y

$22y-5y^2=21$

$5y^2-22y+21=0$

Solve the quadratic equation by graphing

The solutions are y=1.4, y=3

see the attached figure

<em>Find the values of x</em>

For y=1.4

$x=22-5(1.4)=15$

For y=3

$x=22-5(3)=7$

therefore

The solutions are the ordered pairs (7,3) and (15,1.4)

3 0

3 years ago

Factorise completely:<br> 12a+8b

zavuch27 [327]

12a + 8b....common factor is 4
4(3a + 2b) <==

6 0

3 years ago